在Arraylist中删除对象

这里我的问题是，当我在数组中有2个对象时，它会循环2x，然后请求另一个“你确定要删除它吗？”。无法弄清楚我的循环。这里是代码：在Arraylist中删除对象

for (Iterator<Student> it = student.iterator(); it.hasNext();) { 

    Student stud = it.next(); 
    do { 
     System.out.print("Are you sure you want to delete it?"); 
     String confirmDelete = scan.next(); 

     ynOnly = false; 

     if (confirmDelete.equalsIgnoreCase("Y") 
       && stud.getStudNum().equals(enterStudNum2)) { 
      it.remove(); 
      System.out.print("Delete Successful"); 
      ynOnly = false; 
     } else if (confirmDelete.equalsIgnoreCase("N")) { 
      System.out.print("Deletion did not proceed"); 
      ynOnly = false; 
     } else { 
      System.out.println("\nY or N only\n"); 
      ynOnly = true; 
     } 
    } while (ynOnly == true); 

}

来源

2014-10-05 Pun Pun

你应该明白之间的差别了'做/ while'循环和'while'循环:) – nem035 2014-10-05 04:47:21

@Trafalgar法：对于两个对象的名单，你应该看到“你确定...？”两次，并且“删除成功”两次，假设您为循环的每次迭代按'y'/'Y'，并且'stud.getStudNum（）。equals（enterStudNum2）'为'true'。你的输出是什么？ – Voicu 2014-10-05 04:51:19

@Voicu输出是这样的.. 删除成功您确定要删除它吗？它要求另一个确认，而不是只有一个确认 – 2014-10-05 06:04:56

它是因为有两个循环在那里。在ynOnly的值变为false但外循环仍然继续之后，内循环终止。您可能要像that--

for (Iterator<Student> it = student.iterator(); it.hasNext();) { 

Student stud = it.next(); 
if(!stud.getStudNum().equals(enterStudNum2)) 
      continue;       //you want only that student to be deleted which has enterStudNum2 so let other record skip 
do { 
    System.out.print("Are you sure you want to delete it?"); 
    String confirmDelete = scan.next(); 

    ynOnly = false; 

    if (confirmDelete.equalsIgnoreCase("Y") 
      && stud.getStudNum().equals(enterStudNum2)) { 
     it.remove(); 
     System.out.print("Delete Successful"); 
     ynOnly = false; 
    } else if (confirmDelete.equalsIgnoreCase("N")) { 
     System.out.print("Deletion did not proceed"); 
     ynOnly = false; 
    } else { 
     System.out.println("\nY or N only\n"); 
     ynOnly = true; 
    } 
} while (ynOnly == true);

}

来源

2016-01-27 16:13:56 pratapvaibhav19

在Arraylist中删除对象

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