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我得到这个在Xcode 6.1(6A1046a),因为我与6.0:斯威夫特字符串,字符串联加上分配
var dog:String = "Dog"
let plural:Character = "s"
let dogs:String = dog.append(plural)
游乐场报道:
Playground execution failed: :29:23: error: cannot invoke 'append' with an argument of type 'Character' let dogs:String = dog.append(plural)
我为什么不能做这一点,虽然这是罚款:
dog.append(plural)