使用PHP通过Instagram存储json API

Question

我觉得我正在过度揣测这个。我想要做的是从instagram api中拉取最近的照片，并将生成的json信息保存为缓存文件。然后，我将使用jQuery从该文件中读取 - 我已经弄清楚了这一部分。我现在使用的是将其保存在缓存文件中，但不是以我认识的格式保存。我觉得我太过于复杂了。

这是代码，我一直在努力与基于教程中，我发现：

// Client ID for Instagram API 
$instagramClientID = '9110e8c268384cb79901a96e3a16f588'; 

$api = 'https://api.instagram.com/v1/media/popular?client_id='.$instagramClientID; //api  request (edit this to reflect tags) 
$cache = 'cache.txt'; 

if(file_exists($cache) && filemtime($cache) > time() - 60*60){ 
// If a cache file exists, and it is newer than 1 hour, use it 
$images = unserialize(file_get_contents($cache)); 
} 
else{ 
// Make an API request and create the cache file 

// For example, gets the 32 most popular images on Instagram 

$response = file_get_contents($api); //change request path to pull different photos 

$images = array(); 

// Decode the response and build an array 
foreach(json_decode($response)->data as $item){ // Decodes json (javascript) into an array 

    $title = ''; 

    if($item->caption){ 
     $title = mb_substr($item->caption->text,0,70,"utf8"); 
    } 

    $src = $item->images->standard_resolution->url; //Caches standard res img path to variable $src 

    $lat = $item->data->location->latitude; // Caches latitude as $lat 
    $lon = $item->data->location->longtitude; // Caches longitude as $lon  

    $images[] = array(
     "title" => htmlspecialchars($title), 
     "src" => htmlspecialchars($src), 
     "lat" => htmlspecialchars($lat), 
     "lon" => htmlspecialchars($lon) // Consolidates variables to an array 
    ); 
} 

// Remove the last item, so we still have 
// 32 items when when the cover is added 
//array_pop($images); 

// Push the cover in the beginning of the array 
//array_unshift($images,array("title"=>"Cover", "src"=>"assets/img/cover.jpg")); 

// Update the cache file 
file_put_contents($cache,serialize($images)); 
} 

Answer 1

一件事我注意到的是API是超级慢，好选择缓存。

你试图保存为一个序列化的数组（这并不是什么大问题），但是你可以将它另存为json，如果你要再次读取它作为json，它将再次反序列化它将节省1个步骤。

以下是我所做的一些更改： 新增了curl以尝试加快响应速度，或者如果您没有安装，请回退到FGC。 响应被保存为json，当从缓存中检索时，它被解码为一个数组而不是一个对象，这意味着你可以保持相同的数组结构。

$item->data->location->latitude和$item->data->location->longtitude总是在结果空，因此增加了一个检查...

希望它可以帮助

<?php 
// Client ID for Instagram API 
$instagramClientID = '9110e8c268384cb79901a96e3a16f588'; 

$api = 'https://api.instagram.com/v1/media/popular?client_id='.$instagramClientID; //api request (edit this to reflect tags) 
$cache = './cache.json'; 

if(file_exists($cache) && filemtime($cache) > time() - 60*60){ 
    // If a cache file exists, and it is newer than 1 hour, use it 
    $images = json_decode(file_get_contents($cache),true); //Decode as an json array 
} 
else{ 
    // Make an API request and create the cache file 
    // For example, gets the 32 most popular images on Instagram 
    $response = get_curl($api); //change request path to pull different photos 

    $images = array(); 

    if($response){ 
     // Decode the response and build an array 
     foreach(json_decode($response)->data as $item){ 

      $title = (isset($item->caption))?mb_substr($item->caption->text,0,70,"utf8"):null; 

      $src = $item->images->standard_resolution->url; //Caches standard res img path to variable $src 

      //Location coords seemed empty in the results but you would need to check them as mostly be undefined 
      $lat = (isset($item->data->location->latitude))?$item->data->location->latitude:null; // Caches latitude as $lat 
      $lon = (isset($item->data->location->longtitude))?$item->data->location->longtitude:null; // Caches longitude as $lon 

      $images[] = array(
      "title" => htmlspecialchars($title), 
      "src" => htmlspecialchars($src), 
      "lat" => htmlspecialchars($lat), 
      "lon" => htmlspecialchars($lon) // Consolidates variables to an array 
      ); 
     } 
     file_put_contents($cache,json_encode($images)); //Save as json 
    } 
} 

//Debug out 
print_r($images); 

//Added curl for faster response 
function get_curl($url){ 
    if(function_exists('curl_init')){ 
     $ch = curl_init(); 
     curl_setopt($ch, CURLOPT_URL,$url); 
     curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
     curl_setopt($ch, CURLOPT_HEADER, 0); 
     curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); 
     curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); 
     $output = curl_exec($ch); 
     echo curl_error($ch); 
     curl_close($ch); 
     return $output; 
    }else{ 
     return file_get_contents($url); 
    } 

} 

?>