无法解决错误：'int'对象不是可订阅的

我正在尝试使用Python 3.6.2解决Project Euler的问题11。每当我尝试运行我写的代码，并引发错误：无法解决错误：'int'对象不是可订阅的

Traceback (most recent call last): 
    File "E:/Euler11.py", line 6, in <module> 
     product = data[i[j]] 
TypeError: 'int' object is not subscriptable

代码之中：

data = list([[8,2,22,97,38,15,00,40,00,75,4,5,7,78,52,12,50,77,91,8],[49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,4,56,62,00],[81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,3,49,13,36,65],[52,70,95,23,4,60,11,42,69,24,68,56,1,32,56,74,37,2,36,91],[22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80],[24,47,32,60,99,3,45,2,44,75,33,53,78,36,84,20,35,17,12,50],[32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70],[67,26,20,68,2,62,12,20,95,63,94,39,63,8,40,91,66,49,94,21],[24,55,58,5,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72],[21,36,23,9,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95],[78,17,53,28,22,75,31,67,15,94,3,80,4,62,16,14,9,53,56,92],[16,39,5,42,96,35,31,47,55,58,88,24,00,17,54,25,36,29,85,57],[86,56,00,48,35,71,89,7,5,44,44,37,44,60,21,58,51,54,17,58],[19,80,81,68,5,94,47,69,28,73,92,13,86,52,17,77,4,89,55,40],[4,52,8,83,97,35,99,16,7,97,59,32,16,26,26,79,33,27,98,66],[88,36,68,87,58,62,20,75,3,46,33,67,46,55,12,32,63,93,53,69],[4,42,16,73,38,25,39,11,24,94,72,18,8,46,29,32,40,62,76,36],[20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,4,36,16],[20,73,35,29,78,31,90,1,74,31,49,71,48,86,81,16,23,57,5,54],[1,70,54,71,83,51,54,69,16,92,33,48,61,43,52,1,89,19,67,48]]) 
maxProduct = 0 
product = 0 
for i in range(20): 
    for j in range(16): 
     product = data[i[j]] 
     for k in range(1,4): 
      product *= data[i[j+k]] 
     if(product > maxProduct): 
      maxProduct = product 
print(maxProduct)

我会非常感谢所有帮助在向我解释什么，我已经做错了。

来源

2017-08-02 skiller185

'product = data [i] [j]'也许吧。但是你已经硬编码了'i'和'j'的范围。 – roganjosh

'i'将会是一个整数（从0到19）。那么，'我[j]'会是什么？ –

可能是'data [i] [j]'和'data [i] [j + k]' – davedwards

您需要按顺序应用不嵌套的订阅。所以，你应该使用：

data[i][j] 
data[i][j+k]

代替：

data[i[j]] 
data[i[j+k]]

领导下面的（工作）代码：

maxProduct = 0 
product = 0 
for i in range(20): 
    for j in range(16): 
     product = data[i][j] 
     for k in range(1,4): 
      product *= data[i][j+k] 
     if(product > maxProduct): 
      maxProduct = product 
print(maxProduct)

来源

2017-08-02 23:14:43 MSeifert

非常感谢！这是一个很大的帮助。 – skiller185

如果你是在一个2D的数据结构，就像你data并想通过for -loops访问它，正确的方法是

for i in range(height): 
    for j in range(width): 
     some operation using data[i][j]

对于您的情况，您可以使用len来确定高度和宽度。另请注意data[i][j]。如果输入data[i[j]]，Python将尝试使用i的j th元素作为data的索引。

这将使您的代码运行，但不能解决实际问题，因为您必须检查对角线和垂直以及iirc。

来源

2017-08-02 23:25:48 brainfuck4d

无法解决错误：'int'对象不是可订阅的

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