2
我需要比较两个库和更新具有无可比拟的项目在C#中使用LINQ比较字典
两个库是像
Dictionary<String, List<String>> DICTONE = new Dictionary<string, List<String>>();
Dictionary<string, List<String>> DICTTWO = new Dictionary<string, List<String>>();
而内容的另一字典
DICTONE["KEY1"]="A"
"B"
"C"
DICTONE["KEY2"]="D"
"E"
"F"
DICTTWO["KEY1"]="A"
"B"
"Z"
DICTTWO["KEY3"]="W"
"X"
"Y"
的第三个词典有一个类实例,值为
Dictionary<String, MyClass> DICTRESULT = new Dictionary<string, MyClass>();
和类是像
class MyClass
{
public List<string> Additional = null;
public List<string> Missing = null;
public MyClass()
{
Additional = new List<string>();
Missing = new List<string>();
}
public MyClass(List<string> p_Additional, List<string> p_Missing)
{
Additional = p_Additional;
Missing = p_Missing;
}
}
的之情况是
- 如果一个项目在DICTONE而不是在DICTTWO中RESULTDICT
- 的项目添加到失踪名单如果一个项目在DICTTWO中而不是在DICTTONE中将该项目添加到RESULTDICT中的附加列表中
预期的答案是
DICTRESULT["KEY1"]=ADDITIONAL LIST ---> "Z"
MISSING LIST ---> "C"
DICTRESULT["KEY2"]=ADDITIONAL LIST ---> ""
MISSING LIST ---> "D"
"E"
"F"
DICTRESULT["KEY3"]=ADDITIONAL LIST ---> ""
MISSING LIST ---> "W"
"X"
"Y"
有没有办法做到这一点使用LINQ
看起来像功课,你可以显示你已经做了什么? – 2010-07-13 07:27:53
并不多,他已经问过一个非常类似的问题http://stackoverflow.com/questions/3226123/how-to-compare-two-xml-files-in-c-using-xml-to-linq – 2010-07-13 07:31:36