当我取回实体(行)与故意未抓取许多-to-one关联,然后尝试更新实体,我得到了著名瞬态的实例错误:休眠StatelessSession更新多对一不工作(瞬态实例)?
更新对象时出错 对象引用一个未保存的瞬态的实例 - 冲洗
之前保存的瞬态的实例,但“短暂的实例”从来没有取出,并因此甚至不能瞬时
代码:
ProductFamily - java代码
public class ProductFamily
{
private Integer id;
private Company company;
private String name;
//autogenerated getter & setter and constructors
}
ProductFamily - 的hbm.xml
<hibernate-mapping>
<class name="package.ProductFamily" table="product_family" catalog="db">
<id name="id" type="java.lang.Integer">
<column name="id" />
<generator class="identity" />
</id>
<many-to-one name="company" class="package.Company" fetch="select">
<column name="company" not-null="true"/>
</many-to-one>
<property name="name" type="string">
<column name="name" length="64" not-null="true"/>
</property>
</class>
</hibernate-mapping>
公司 - java代码
public class Company
{
private String name;
private Set<ProductFamily> productFamilies = new HashSet<ProductFamily>(0);
//autogenerated getter & setter and constructors
}
公司 - 的hbm.xml
<!-- same header as above -->
<hibernate-mapping>
<class name="package.Company" table="company" catalog="db">
<id name="id" type="java.lang.Integer">
<column name="id" />
<generator class="identity" />
</id>
<property name="name" type="string">
<column name="name" length="64" not-null="true"/>
</property>
<set name="productFamilies" table="product_family" inverse="true" lazy="true" fetch="select">
<key>
<column name="company" not-null="true"/>
</key>
<one-to-many class="package.ProductFamily" />
</set>
</class>
</hibernate-mapping>
测试方法简单检索和更改和更新
public void test()
{
final StatelessSession session = this.sessionFactory.openStatelessSession();
//get
final ProductFamily productFamily = (ProductFamily)session.get(ProductFamily.class, 1);
//change primitive property
productFamily.setName(productFamily.getName() + "x");
//update
final Transaction tr = session.beginTransaction();
try
{
session.update(productFamily);
tr.commit();
}
catch (HibernateException e)
{
logger.severe(e.getMessage() + "\n" + e.getStackTrace());
try
{
if(tr != null
&& tr.isActive())
tr.rollback();
}
catch (HibernateException eTr)
{
logger.severe(eTr.getMessage() + "\n" + eTr.getStackTrace());
}
}
finally
{
session.close();
}
}
请显示您的代码。关于故意取消关联,修改实体和“更新”的部分。 – 2012-04-16 17:12:14
我添加了一个仍然产生相同错误的简单示例。 – djmj 2012-04-16 22:28:24