org.hibernate.hql.internal.ast.QuerySyntaxException路径无效

Question

我在jsf中设计了类别和子类别表单。当我选择任何类别时，与该类别相关的子类别将在下拉菜单中显示。我有一个问题如何编写hql文件。类别和子类别取决于onetomany，反之亦然。

这是下面的子类别dao。

public List getAllSubCategoriesSelectItemName(String name) { 
    // TODO Auto-generated method stub 
    Session session = HibernateUtil.getSessionFactory().openSession(); 

    try { 

     List<Category> liste = session.createQuery("Select S.SubName from SubCategory S left join SC.category scc where scc.name='"+name+"'").list(); 
     return liste; 


    } catch (Exception e) { 
     e.printStackTrace(); 

    }finally { 

     session.close(); 

    } 
    return null; 
} 



    @Entity 
    @Table(name="CATEGORY",schema="DEMO") 
    public class Category implements Serializable{ 

    @Id 
@SequenceGenerator(name="catseq",sequenceName="seqCatSEQ",allocationSize=1) 
    @GeneratedValue(generator="catseq",strategy=GenerationType.SEQUENCE) 
    @Column(name="ID") 
    private Integer id; 

    @Column(name="NAME") 
    private String name; 

    @Column(name="CAT_DESC") 
    private String catDesc; 


    @OneToMany(cascade = { CascadeType.PERSIST },mappedBy="category") 
    private Set<SubCategory> subcategories = new HashSet(); 

    public Category() { 
     super(); 
     // TODO Auto-generated constructor stub 
    } 


    public Category(String name, String catDesc) { 
     super(); 
     this.name = name; 
     this.catDesc = catDesc; 
    } 


    public Integer getId() { 
     return id; 
    } 

    public void setId(Integer id) { 
     this.id = id; 
    } 

    public String getName() { 
     return name; 
    } 

    public void setName(String name) { 
     this.name = name; 
    } 

    public String getCatDesc() { 
     return catDesc; 
    } 

    public void setCatDesc(String catDesc) { 
     this.catDesc = catDesc; 
    } 


    public Set<SubCategory> getSubcategories() { 
     return subcategories; 
    } 


    public void setSubcategories(Set<SubCategory> subcategories) { 
     this.subcategories = subcategories; 
    } 


} 

package entities; 

import java.io.Serializable; 
import java.util.HashSet; 
import java.util.Set; 

import javax.persistence.CascadeType; 
import javax.persistence.Column; 
import javax.persistence.Entity; 
import javax.persistence.GeneratedValue; 
import javax.persistence.GenerationType; 
import javax.persistence.Id; 
import javax.persistence.JoinColumn; 
import javax.persistence.ManyToMany; 
import javax.persistence.ManyToOne; 
import javax.persistence.OneToMany; 
import javax.persistence.SequenceGenerator; 
import javax.persistence.Table; 


@Entity 
@Table(name="SUBCATEGORY",schema="DEMO") 
public class SubCategory implements Serializable{ 

    @Id 
    @SequenceGenerator(name="subcatseq",sequenceName="seqSubCatSEQ",allocationSize=1) 
    @GeneratedValue(generator="subcatseq",strategy=GenerationType.SEQUENCE) 
    @Column(name="ID") 
    private Integer id; 

    @Column(name="SUBNAME") 
    private String SubName; 

    @Column(name="SUBNAME_DESC") 
    private String SubNameDes; 

    @ManyToOne(cascade={CascadeType.PERSIST,CascadeType.REMOVE}) 
    @JoinColumn(name = "CAT_ID") 
    private Category category; 

    @ManyToMany(cascade=CascadeType.PERSIST,mappedBy="subcategories") 
    Set<Product> products = new HashSet<Product>(); 


    public SubCategory() { 
     super(); 
     // TODO Auto-generated constructor stub 
    } 

    public SubCategory(String subName, String subNameDes) { 
     super(); 
     SubName = subName; 
     SubNameDes = subNameDes; 
    } 

    public Integer getId() { 
     return id; 
    } 

    public void setId(Integer id) { 
     this.id = id; 
    } 

    public String getSubName() { 
     return SubName; 
    } 

    public void setSubName(String subName) { 
     SubName = subName; 
    } 

    public String getSubNameDes() { 
     return SubNameDes; 
    } 

    public void setSubNameDes(String subNameDes) { 
     SubNameDes = subNameDes; 
    } 


    public Category getCategory() { 
     return category; 
    } 

    public void setCategory(Category category) { 
     this.category = category; 
    } 



} 

Answer 1

Select S.SubName from SubCategory S left join SC.category 

没有什么在query.The仅存的别名是S与SC别名。所以SC.category是不正确的。