从JSON中删除ID，然后将其添加到每组数据中。

我一直在运行一个Python脚本，它删除每组数据的ID，以允许它上传到BigQuery。现在，我不想删除这些信息，而是想将其插入每组数据中，以便稍后参考。从JSON中删除ID，然后将其添加到每组数据中。

这就是我一直在接收JSON，并将其上传到BigQuery中的代码。

{"AppName": "DataWorks", "foundedPeripheralCount": 1, "version": "1.6.1(8056)", "deviceType": "iPhone 6", "createdAt": "2017-04-05T07:05:30.408Z", "updatedAt": "2017-04-05T07:08:49.569Z", "connectedPeripheralCount": 1, "iOSVersion": "10.2.1"}

firebase = firebase.FirebaseApplication('https://dataworks-356fa.firebaseio.com/') 
result = firebase.get('/PeripheralCount', None) 
id_keys = map(str, result.keys()) #filter out ID names 


with open("firetobq_peripheral2.json", "w") as outfile: 
    for id in id_keys: 
    json.dump(result[id], outfile, indent=None) 
    outfile.write("\n")

这是JSON的方式，而不与代码一起任何编辑创建。

{"1972FDEE-E2C0-4E8C-BD00-630315D4AEDE": {"AppName": "DataWorks", "foundedPeripheralCount": 1, "version": "1.6.1(8056)", "deviceType": "iPhone 6", "connectedPeripheralCount": 1, "updatedAt": "2017-04-05T07:08:49.569Z", "Peripherals": {"1CA726ED-32B1-43B4-9071-B58BBACE20A8": "Arduino"}, "createdAt": "2017-04-05T07:05:30.408Z", "iOSVersion": "10.2.1"}

其中1972FDEE-E2C0-4E8C-BD00-630315D4AEDE是ID。

firebase = firebase.FirebaseApplication('https://dataworks-356fa.firebaseio.com/') 
result = firebase.get('/PeripheralCount', None) 
id_keys = map(str, result.keys()) #filter out ID names 


with open("firetobq_peripheralx.json", "w") as outfile: 
    # for id in id_keys: 
    json.dump(result, outfile, indent=None) 
    outfile.write("\n")

我希望它看起来像这样。

{"ID": "1972FDEE-E2C0-4E8C-BD00-630315D4AEDE", "AppName": "DataWorks", "foundedPeripheralCount": 1, "version": "1.6.1(8056)", "deviceType": "iPhone 6", "connectedPeripheralCount": 1, "updatedAt": "2017-04-05T07:08:49.569Z", "Peripherals": {"1CA726ED-32B1-43B4-9071-B58BBACE20A8": "Arduino"}, "createdAt": "2017-04-05T07:05:30.408Z", "iOSVersion": "10.2.1"}

感谢您的帮助！

来源

2017-07-27 W. Stephens

首先定义一个基dict保存您的ID：

out = { 
    "ID": "1972FDEE-E2C0-4E8C-BD00-630315D4AEDE", 
}

然后，更新out与原点JSON：

out.update(js_dict.get(out.get('ID')))

js_dict是你上面提到的JSON。

来源

2017-07-27 03:32:48 LuCima

从JSON中删除ID，然后将其添加到每组数据中。

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