2012-03-26 52 views
0

我已经将Silverlight工具包添加到我的WP7应用程序中。WP7中Silverlight工具包的问题

<Button Content="Country"> 
    <toolkit:ContextMenuService.ContextMenu> 
     <toolkit:ContextMenu> 
      <toolkit:MenuItem Header="England" Tag="1" Click="set_country" /> 
      <toolkit:MenuItem Header="Germany" Tag="2" Click="set_country" /> 
      <toolkit:MenuItem Header="France" Tag="3" Click="set_country" /> 
      <toolkit:MenuItem Header="Spain" Tag="4" Click="set_country" /> 
      <toolkit:MenuItem Header="Italy" Tag="5" Click="set_country" /> 
     </toolkit:ContextMenu> 
    </toolkit:ContextMenuService.ContextMenu> 
</Button> 

处理程序:

private void set_country(object sender, MouseEventArgs e) 
{ 
    var menuItem = (MenuItem)sender; 
    var tag = menuItem.Tag.ToString(); 
    MessageBox.Show(tag); 
} 

但它在这个字符串中MainPage.gics问题:

this.LayoutRoot = ((System.Windows.Controls.Grid)(this.FindName("LayoutRoot"))); 

错误:无法分配财产“Microsoft.Phone.Controls。 MenuItem.Click”。 [行:31职位:72]

+1

请不要发誓。我不知道wp7工具包,但你对mouseeventargs是否正确?不应该是RoutedEventargs? – Silvermind 2012-03-26 16:32:50

回答

2

事件处理程序的签名是错误的:

private void MenuItem_Click(object sender, RoutedEventArgs e) 
{ 
    MenuItem menuItem = (MenuItem)sender; 
    MessageBox.Show("You chose to " + menuItem.Header.ToString(),"Result",MessageBoxButton.OK); 
}