无法通过使用curl将表单中的动态数据传递给API

Question

我有一个表单，我希望捕获值并将其传递到json格式的api中，以便使用以下代码。

<?php 
$name = $this->input->post('name'); 
$location = $this->input->post('location'); 
$age = $this->input->post('age'); 

$ch = curl_init(); 

curl_setopt($ch, CURLOPT_URL, "https://example.com"); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
curl_setopt($ch, CURLOPT_POSTFIELDS, "{ 
    'name' => $name, 
    'location' => $location, 
    'age' => $age 
}"); 

curl_setopt($ch, CURLOPT_POST, 1); 

$headers = array(); 
$headers[] = "Apikey: ***"; 
$headers[] = "Cache-Control: no-cache"; 
$headers[] = "Content-Type: application/json"; 
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); 

$result = curl_exec($ch); 

$http_status = curl_getinfo($ch, CURLINFO_HTTP_CODE); 

print_r($http_status); 

echo "<br>"; 

if (curl_errno($ch)) { 
    echo 'Error:' . curl_error($ch); 
} 
curl_close ($ch); 

print_r($result); 
?> 

我收到以下错误

对于HTTP_STATUS我收到错误

400

并为$结果我得到错误

[Invalid Json: Unexpected character (''' (code 39)): was expecting double-quote to start field name at [Source: akka.util.ByteIterator$ByteArrayIterator$$anon$1@1a18f8fc; line: 3, column: 3]]

为了解决上面提到的问题，如果我尝试给双引号，然后我得到PHP语法错误

任何人都可以请告诉我如何成功发送数据

Answer 1

不要发明车轮。传递数据时使用json_encode：

$post_fields = array(
    'name' => $name, 
    'location' => $location, 
    'age' => $age 
); 
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($post_fields));