2009-04-19 78 views
0

这个问题的标题应该是不言自明,但基本上我有这样的代码(工作)上传通过HTTP文件和读取结果在C#

 progfrm = new progressform(); 
     System.Net.WebClient ahwebclient = new System.Net.WebClient(); 
     progfrm.Show(); 
     ahwebclient.UploadProgressChanged += new System.Net.UploadProgressChangedEventHandler(ahwebclient_UploadProgressChanged); 
     ahwebclient.UploadFileCompleted += new System.Net.UploadFileCompletedEventHandler(ahwebclient_UploadFileCompleted); 
     ahwebclient.UploadFileAsync(new Uri("http://upload.anyhub.net/bin/demovu_upload.php"), "C:/install.exe"); 
     while (ahwebclient.IsBusy) 
     { 
      Application.DoEvents(); 
     } 

我将如何读这个请求的这个结果一旦它完成了吗?

+0

什么是你`ahwebclient_UploadFileCompleted`事件处理方法? – 2009-04-19 23:48:36

+0

void ahwebclient_UploadFileCompleted(object sender,System.Net.UploadFileCompletedEventArgs e) progfrm.Close(); progfrm.Dispose(); } – 2009-04-19 23:49:39

回答