C＃XML与属性序列化的每一个元素

Question

我想创建以下XML：

<StartLot> 
     <fileCreationDate level="7">201301132210</fileCreationDate> 
     <fmtVersion level="7">3.0</fmtVersion> 
</StartLot> 

下面是序列化代码：

[Serializable] 
class StartLot 
{ 
    public fileCreationDate{get; set;} 

    [XmlAttribute("level")] 
    public string level = "7"; 

    public fmtVersion{get; set;} 

    [XmlAttribute("level")] 
    public string level = "7"; ?? 
} 

既然我已经声明属性级别，我该怎么加最后一个属性？

Answer 1

您可以使用一个包装类来存储值，如下面的例子：

public class StackOverflow_15441384 
{ 
    const string XML = @"<StartLot> 
           <fileCreationDate level=""7"">201301132210</fileCreationDate> 
           <fmtVersion level=""7"">3.0</fmtVersion> 
          </StartLot>"; 
    public class StartLot 
    { 
     [XmlElement("fileCreationDate")] 
     public LevelAndValue FileCreationDate { get; set; } 
     [XmlElement("fmtVersion")] 
     public LevelAndValue FmtVersion { get; set; } 
    } 
    public class LevelAndValue 
    { 
     [XmlAttribute("level")] 
     public string Level { get; set; } 
     [XmlText] 
     public string Value { get; set; } 
    } 
    public static void Test() 
    { 
     XmlSerializer xs = new XmlSerializer(typeof(StartLot)); 
     StartLot sl = (StartLot)xs.Deserialize(new MemoryStream(Encoding.UTF8.GetBytes(XML))); 
     Console.WriteLine("FCD.L = {0}", sl.FileCreationDate.Level); 
     Console.WriteLine("FCD.V = {0}", sl.FileCreationDate.Value); 
     Console.WriteLine("FV.L = {0}", sl.FmtVersion.Level); 
     Console.WriteLine("FV.V = {0}", sl.FmtVersion.Value); 
    } 
} 

Answer 2

我总能找到Linq To Xml更容易使用

var xDoc = XDocument.Parse(xml); /* XDocument.Load(filename); */ 

var items = xDoc.Root.Descendants() 
       .Select(e => new 
       { 
        Name = e.Name.LocalName, 
        Level = e.Attribute("level").Value, 
        Value = e.Value 
       }) 
       .ToList();