字符串中的每个字母不同的颜色，HTML PHP

我需要使用仅HTML和PHP打印不同颜色（不随机颜色）的字符串的每个字符。它几乎可以工作，但阵列的第一个字母是黑色的。你知道为什么吗？字符串中的每个字母不同的颜色，HTML PHP

<html> 
    <?php 
     $myString = ["s","t","r","i","n","g"]; 
     $myColors = ["blue","green","yellow","brown","gray","pink"]; 

     for ($i = 0; $i < count($myString); $i++) { 
      echo "$myString[$i] <span style='color:$myColors[$i]'</span>"; 
     } 
    ?> 
</html>

来源

2017-06-06 kales

看看你的标记，其中字母内跨越....加的事实，你没有结束'>'的跨度 –

好像你没有正确关闭你的span标记，并且将你的字符串放入你的span中将有助于着色它。

<?php 
$myString = ["s","t","r","i","n","g"]; 
$myColors = ["blue","green","yellow","brown","gray","pink"]; 

for ($i = 0; $i < count($myString); $i++) { 
    echo "<span style='color:$myColors[$i]'>$myString[$i]</span>"; 
}

来源

2017-06-06 15:37:59 reinierkors

的字符不是彩色跨度内，你缺少一个>：

echo "<span style='color:$myColors[$i]'>$myString[$i]</span>";

来源

2017-06-06 15:38:04 Halcyon

我觉得你的HTML被打破了。您需要在<span>元素内包含$myString[$i]并正确关闭它。

$myString = ["s","t","r","i","n","g"]; 
$myColors = ["blue","green","yellow","brown","gray","pink"]; 

for ($i = 0; $i < count($myString); $i++) { 
    echo "<span style='color:$myColors[$i]'>$myString[$i]</span>"; 
}

来源

2017-06-06 15:38:05

<html> 
<?php 
$myString = ["s","t","r","i","n","g"]; 
$myColors = ["blue","green","yellow","brown","gray","pink"]; 

for ($i = 0; $i < count($myString); $i++) { 

    echo "<span style='color:$myColors[$i]'> $myString[$i] </span>"; 

} 
?> 
</html>

来源

2017-06-06 15:54:19

字符串中的每个字母不同的颜色，HTML PHP

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