3
此代码的目的是创建一个凯撒密码,只用3个键编码字母数字字符,其中第一个字母由第一个键递增,第二个字符由第二个键递增,第三个字符为(Z + 1 - > a),(a - 1 - > Z)的第一个键,第三个键,第四个字符等。凯撒密码问题(C)
我完全完成了作业,唯一的问题是我的负面环绕不起作用(a - 1 - > Z)。它要求输入密钥,接受输入,然后不返回任何内容(但仍然允许用户输入并按回车键而不带任何结果)。这里是我的代码:
#include <stdio.h>
#include <math.h>
#include <string.h>
#include <stdlib.h>
char sentence[101] = { '\0' };
char alphabet[52]={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
int locateletter(char tolocate){
int i=0;
for(i=0; i<52; i++){
if(alphabet[i] == tolocate)
return i;
}
}
int main(void){
int key1 = 0;
int key2 = 0;
int key3 = 0;
printf("Sentence: ");
scanf("%101[^\n]", sentence);
if(sentence[100] != '\0'){
printf("You entered more than 100 characters. Block Caesar Cipher is exiting. Goodbye.\n");
exit;
}else{
printf("Keys: ");
scanf("%d %d %d", &key1, &key2, &key3);
int i=0;
for(i=0; i<100; i=i+3){
if(isalpha(sentence[i])){
int position = locateletter(sentence[i]);
while((position+key1)>51){
key1 = position+key1-52;
position=0;
}
while((position+key1)<0){
key1 = key1+position+52;
position=0;
}
sentence[i] = alphabet[position+key1];
}
}
int k=1;
for(k=1; k<100; k=k+3){
if(isalpha(sentence[k])){
int position = locateletter(sentence[k]);
while((position+key2)>51){
key2 = position+key2-52;
position=0;
}
while((position+key2)<0){
key1 = key2+position+52;
position=0;
}
sentence[k] = alphabet[position+key2];
}
}
int t=2;
for(t=2; t<100; t=t+3){
if(isalpha(sentence[t])){
int position = locateletter(sentence[t]);
while((position+key3)>51){
key3 = position+key3-52;
position=0;
}
while((position+key3)<0){
key1 = key3+position+52;
position=0;
}
sentence[t] = alphabet[position+key3];
}
}
printf("Cipher: %s\nDone.\n", sentence);
}
return 0;
}
+1良好的首次发贴和良好的自我回答。 – chux 2014-10-16 16:43:09