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我想分区我的表。 表是:没有唯一字段的mysql分区
create_table "multimedia", :force => true do |t|
t.integer "id"
t. binary "data"
t.integer "device_id"
t.datetime "created_at"
end
id
是主键
created_at是表的简单索引并没有独特
我需要由现场created_at对表进行分区。在我的桌子里只有最近7天的记录,所以我想在一天之内进行分区。我写这篇文章COSE:
partition by range (to_days(created_at))
(PARTITION p20120417 VALUES LESS THAN (to_days('2012-04-17 23:59:59 +0200')),
PARTITION p20120418 VALUES LESS THAN (to_days('2012-04-18 23:59:59 +0200')),
PARTITION p20120419 VALUES LESS THAN (to_days('2012-04-19 23:59:59 +0200')),
PARTITION p20120420 VALUES LESS THAN (to_days('2012-04-20 23:59:59 +0200')),
PARTITION p20120421 VALUES LESS THAN (to_days('2012-04-21 23:59:59 +0200')),
PARTITION p20120422 VALUES LESS THAN (to_days('2012-04-22 23:59:59 +0200')),
PARTITION p20120423 VALUES LESS THAN (to_days('2012-04-23 23:59:59 +0200')),
PARTITION p20120424 VALUES LESS THAN (to_days('2012-04-24 23:59:59 +0200'))
);
代码给我这个错误:
A PRIMARY KEY must included all columns in the table's partitioning function
我需要的表分区只有created_at,它不能是唯一的。
我该怎么办?
欢迎来到Stack Overflow。您可以使用工具栏按钮格式化源代码块(或向所有行添加4个字符的缩进)。这次我为你做了。 – 2012-04-26 10:36:15