提交PHP的形式谷歌文档

Question

这是我的HTML表单的使用jQuery

<form target="_self" onsubmit="" action="javascript: postContactToGoogle()" method="post" onsubmit=""> 
     <span id="form-error"><?php if(isset($_SESSION['alert'])){ echo $_SESSION['alert']; unset($_SESSION['alert']);} ?></span> 
     <div class="form-group"> 
     <p class="no-margin bottom5">YOUR NAME (required)</p> 
     <input type="text" class="form-control" name="name" id="name" required> 
     </div> 
     <div class="form-group"> 
     <p class="no-margin bottom5">YOUR EMAIL (required)</p> 
     <input type="email" class="form-control" name="email" id="email" required> 
     </div> 
     <div class="form-group"> 
     <p class="no-margin bottom5">MESSAGE</p> 
     <textarea class="form-control" rows="5" id="message" name="message"></textarea> 
     </div> 
     <button class="btn btn-default" type="submit">Send</button> 
     <div style="width: 100%; display: block; float: right; padding-top: 15px;"> 
     <div class="requestSubmited" style="display:none; text-align: center;">Your request has been sent!</div> 
    </div> 
    </form> 

这是我的jQuery

function postContactToGoogle(){ 
    var name = $('#name').val(); 
    var email = $('#email').val(); 
    var message = $('#message').val(); 

     $.ajax({ 
      url: "https://docs.google.com/a/mapplinks.com/forms/d/1r3SISt7ocWE32s7LJxBOOteMeMV-JTy166pH87hxwF4/formResponse", 
      data: {"entry.2028011364" : name, "entry.1745855979" : email, "entry.919224434": message}, 
      type: "POST", 
      dataType: "xml", 
      statusCode: { 
       0: function(){ 

        alert("saved0"); 
        //Success message 
       }, 
       200: function(){ 
        alert("saved"); 
        //Success Message 
       } 
      } 
     }); 


} 

提交这是我的形式和jQuery我一直using.Im得到响应0但谷歌形式没有得到updated.Please帮我在这

Answer 1

只要按照指导：

https://wiki.base22.com/pages/viewpage.action?pageId=72942000

这会有所帮助。