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我有,目前有两种颜色的渐变一个mixin:如何在mixin中处理可变数量的参数?
@mixin gradient($color-start, $color-end) {
background-image: linear-gradient(90deg, $color-start 0%, $color-end 100%);
}
,我到处使用像这样
.my-gradient {
@include gradient(blue, yellow)
}
,但现在我想修改混入(或将其转换为一个函数),可以采用两个或三个参数作为渐变。
像(伪代码):
@mixin gradient($color-start, $color-end, $color-center) {
...if $color-center param exists...
background-image: linear-gradient(90deg, $color-start 0%, $color-center 50%, $color-end 100%);
...if $color-center param does not exist...
background-image: linear-gradient(90deg, $color-start 0%, $color-end 100%);
}
我不知道的处理这种情况的最好办法。
这是否回答帮助? https://stackoverflow.com/a/9960403/5561605 – sol