2012-03-06 52 views
3

我正在尝试Phonegap的Camera API,并且遇到了问题。从官方文档使用的代码:Phonegap + JQM - Camera API,无法查看捕获的照片

<script type="text/javascript" charset="utf-8"> 

    var pictureSource; // picture source 
    var destinationType; // sets the format of returned value 

    // Wait for PhoneGap to connect with the device 
    // 
    document.addEventListener("deviceready",onDeviceReady,false); 

    // PhoneGap is ready to be used! 
    // 
    function onDeviceReady() { 
     pictureSource=navigator.camera.PictureSourceType; 
     destinationType=navigator.camera.DestinationType; 
    } 

    // Called when a photo is successfully retrieved 
    // 
    function onPhotoDataSuccess(imageData) { 
     // Uncomment to view the base64 encoded image data 
     // console.log(imageData); 

     // Get image handle 
     // 
     var smallImage = document.getElementById('smallImage'); 

     // Unhide image elements 
     // 
     smallImage.style.display = 'block'; 

     // Show the captured photo 
     // The inline CSS rules are used to resize the image 
     // 
     smallImage.src = "data:image/jpeg;base64," + imageData; 
    } 

    // Called when a photo is successfully retrieved 
    // 
    function onPhotoURISuccess(imageURI) { 
     // Uncomment to view the image file URI 
     // console.log(imageURI); 

     // Get image handle 
     // 
     var largeImage = document.getElementById('largeImage'); 

     // Unhide image elements 
     // 
     largeImage.style.display = 'block'; 

     // Show the captured photo 
     // The inline CSS rules are used to resize the image 
     // 
     largeImage.src = imageURI; 
    } 

    // A button will call this function 
    // 
    function capturePhoto() { 
     // Take picture using device camera and retrieve image as base64-encoded string 
     navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50 }); 
    } 

    // A button will call this function 
    // 
    function capturePhotoEdit() { 
     // Take picture using device camera, allow edit, and retrieve image as base64-encoded string 
     navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true }); 
    } 

    // A button will call this function 
    // 
    function getPhoto(source) { 
     // Retrieve image file location from specified source 
     navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50, 
     destinationType: destinationType.FILE_URI, 
     sourceType: source }); 
    } 

    // Called if something bad happens. 
    // 
    function onFail(message) { 
     alert('Failed because: ' + message); 
    } 

    </script> 

我的按钮:

<button onclick="capturePhoto();">Capture Photo</button> 

和IMG标签:

<img style="display:none;width:60px;height:60px;" id="smallImage" src="" /> 

相机开辟了罚款,并拍照没有问题,但是,它不会显示在页面上。

我有更多的代码可以让你从相册中选择一个图像,这完美地工作,显示在不同的图像标签。

我认为问题在于它无法找到imageData。

拍摄的照片确实被保存到手机中,并且可以使用其他按钮显示,但我希望在拍摄照片后可以直接显示。

我使用JQM btw和使用Phonegap编译我的APK:构建web编译器。

回答

5

Phonegap上的文档是错误的。要获得base64编码的图片,你需要调用

navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality:50, destinationType:Camera.DestinationType.DATA_URL }); 
+0

经过测试,返回文件位置而不是base64 ... – SAFAD 2012-11-04 20:17:34

0

这是很容易和更清洁的使用文件URI(但如果你想要的形象坚持,iOS上的图像保存到临时文件夹要小心 - http://docs.phonegap.com/en/1.7.0/cordova_camera_camera.md.html#Camera)。您可以显示图片马上如下:

navigator.camera.getPicture(displayPicture, function(err){}, {quality : 40, 
     destinationType : Camera.DestinationType.FILE_URI, 
     sourceType : Camera.PictureSourceType.CAMERA}); 

function displayPicture(file_uri){ 
var img_tag = '<img style="width:60px;height:60px;" id="smallImage" src="'+file_uri+'" />'; 
//Attach the img tag where ever you want it ... $(<some parent tag>).append(img_tag) etc. 

} 
+0

这两个都不返回base64 – SAFAD 2012-11-04 20:36:50

0

在CapturePhoto()函数,添加此选项;

destinationType : Camera.DestinationType.FILE_URI, 

随着PhoneGap的说,使用FILE_URI是拍摄照片与新一代手机的最佳实践。

要显示图像,请在getPhotoDataSuccess中使用此方法;

$('#smallImage').attr("src",imageURI);