-3
这是我的LU分解CROUT方法代码:LU分解CROUT减少
function [L, U] = croutreduction(A)
[row,column]=size(A);
L=eye(row,column);
//A = 3x3
if row==3 then
U(1,1)=A(1,1); U(1,2)=A(1,2); U(1,3)=A(1,3);
L(2,1)=A(2,1)/U(1,1); L(3,1)=A(3,1)/U(1,1);
U(2,2)=A(2,2)-L(2,1)*U(1,2);
U(2,3)=A(2,3)-L(2,1)*U(1,3);
L(3,2)=A(3,2)/U(2,2);
U(3,3)=A(3,3)-L(3,2)*U(2,3);
end
//A = 4x4
if column==4 then
U(1,1)=A(1,1); U(1,2)=A(1,2); U(1,3)=A(1,3); U(1,4)=A(1,4);
L(2,1)=A(2,1)/U(1,1); L(3,1)=A(3,1)/U(1,1); L(4,1)=A(4,1)/U(1,1);
U(2,2)=A(2,2)-L(2,1)*U(1,2);
U(2,3)=A(2,3)-L(2,1)*U(1,3);
U(2,4)=A(2,4)-L(2,1)*U(1,4);
L(3,2)=(A(3,2)-L(3,1)*U(1,2))/U(2,2);
L(4,2)=(A(4,2)-L(4,1)*U(1,2))/U(2,2);
U(3,3)=A(3,3)-(L(3,1)*U(1,3)+L(3,2)*U(2,3));
U(3,4)=A(3,4)-(L(3,1)*U(1,4)+L(3,2)*U(2,4));
L(4,3)=(A(4,3)-(L(4,1)*U(1,3)+L(4,2)*U(2,3)))/U(3,3);
U(4,4)=A(4,4)-(L(4,1)*U(1,4)+L(4,2)*U(2,4)+L(4,3)*U(3,4));
end
endfunction
如何修改我的代码具有不同尺寸的矩阵来工作?如您所见,上面的代码仅适用于3x3和4x4矩阵。
Crout缩减代码是通过谷歌avaialbe和关于第一个问题,请尝试做到这一点,并在您有任何问题和问题后,我们将更乐意帮助您 – madbitloman 2015-04-04 21:47:59
您可以检查我的新代码? – 2015-04-06 16:33:15
如果您有N维矩阵,我建议您将其重新整形为正方形2D矩阵,然后执行反演,然后重新整形。 – madbitloman 2015-04-06 17:49:51