我已经得到了这个脚本工作正常,允许用户投票,但我是如何使投票按钮的东西,当再次点击它切换回正常图像!就像计算器:jquery使用jQuery切换事件切换投票?
这是我的脚本:
$(document).ready(function() {
$('.statuses').delegate('.vote_up', 'click', function(e) {
//stop event
e.preventDefault();
//get the id
var the_id = $(this).closest('.message').attr('id').split('_').pop();
//the main ajax request
$.ajax({
context: this,
type: "POST",
// Make sure "this" in the callback refers to the element clicked
data: "action=vote_up&id=" + the_id,
url: "ajax/votes.php",
success: function (msg) {
$(this).siblings("span.vote_count").html(msg).fadeIn();
// get the child <img> and set its src
$(this).children("img").attr("src", "img/uparrowActive.png");
}
});
});
HTML:
<ul class="statuses">
<li id="set_41" class="message">
<span class="vote_count">0</span>
<a href="#" class="vote_up"><img src="img/uparrow.png" /></a>
这是我希望发生伪语言:
a user clicks vote image, it changes the image(uparrowActive)
//I've done that already
then
if user clicks the same image again it goes back to normal image(uparrow)
了解CSS sprites。 – BalusC 2010-10-12 18:34:57
你好我在完成我的应用程序后要这样做,但我试图先把所有东西放在一起! – getaway 2010-10-12 18:36:48