我有简单的情况下(如图像link text上)和简单的SQL查询NHibernate的加入和投影性能
SELECT M.Name,
A.Name,
B.Name
FROM Master M LEFT JOIN DetailA A
ON M.DescA = A.Id LEFT JOIN DetailB B
ON M.DescB = B.Id
如何才达到NHibernate的使用CriteriaAPI同样的效果?
我有这样的事情:
public class Employee : ClassBase, IContactData
{
public virtual string FirstName { get; set; }
public virtual string MiddleName { get; set; }
public virtual string LastName { get; set; }
public virtual string NickName { get; set; }
public virtual string Login { get; set; }
public virtual string Password { get; set; }
public virtual string ContactPerson { get; set; }
public virtual string PESEL { get; set; }
public virtual string IdentificationNo { get; set; }
public virtual string NIP { get; set; }
public virtual string Description { get; set; }
public virtual string Profession { get; set; }
public virtual byte[] Photo { get; set; }
public virtual DateTime? BirthDate { get; set; }
public virtual Boolean SpecialUser { get; set; }
public virtual Boolean Sex { get; set; }
public virtual Item Gender { get; set; }
public virtual Item Position { get; set; }
public virtual Item Status { get; set; }
public virtual Item Nation { get; set; }
public virtual Item Education { get; set; }
public virtual Item JobType { get; set; }
public virtual ISet<Address> Addresses { get; set; }
}
public class Item : ClassBase
{
public virtual int ItemCode { get; set; }
public virtual int DictCode{ get; set;}
public virtual string Description{ get; set;}
public override string ToString()
{
return Description;
}
}
public class Address : ClassBase
{
public virtual string Description { get; set; }
public virtual string District { get; set; }
public virtual string Community { get; set; }
public virtual string City { get; set; }
public virtual string Street { get; set; }
public virtual string PostalCode { get; set; }
public virtual string HouseNo { get; set; }
public virtual string FlatNo { get; set; }
public virtual Boolean Official { get; set; }
public virtual Item Country { get; set; }
public virtual Item Region { get; set; }
}
映射:
<property name="FirstName" column="FIRST_NAME" type="string" length="50" not-null="true"/>
<property name="MiddleName" column="MIDDLE_NAME" type="string" length="50" not-null="false"/>
<property name="LastName" column="LAST_NAME" type="string" length="50" not-null="true"/>
<property name="NickName" column="NICKNAME" type="string" length="50" not-null="false"/>
<property name="Login" column="LOGIN" type="string" length="30" not-null="false"/>
<property name="Password" column="PASSWORD" type="string" length="100" not-null="false"/>
<property name="ContactPerson" column="CONTACT_PERSON" type="string" length="250" not-null="false"/>
<property name="PESEL" column="PESEL" type="string" length="11" not-null="false"/>
<property name="IdentificationNo" column="IDENTIFICATION_NO" type="string" length="12" not-null="false"/>
<property name="NIP" column="NIP" type="string" length="11" not-null="false"/>
<property name="Description" column="DESCRIPTION" type="string" length="1000" not-null="false"/>
<property name="Profession" column="PROFESSION" type="string" length="150" not-null="false"/>
<property name="BirthDate" column="BIRTH_DATE" type="DateTime" not-null="false"/>
<property name="Photo" column="PHOTO" type="BinaryBlob" not-null="false"/>
<property name="Sex" column="SEX" type="Boolean" not-null="false"/>
<property name="SpecialUser" column="SPECIAL_USER" type="Boolean" not-null="false"/>
<many-to-one name="Gender" column="DIC_GENDER" not-null="false" class="DomainModel.ERP.Item,DomainModel" />
<many-to-one name="Position" column="DIC_POSITION" not-null="false" class="DomainModel.ERP.Item,DomainModel" />
<many-to-one name="Status" column="DIC_STATUS" not-null="false" class="DomainModel.ERP.Item,DomainModel" />
<many-to-one name="Nation" column="DIC_NATION" not-null="false" class="DomainModel.ERP.Item,DomainModel" />
<many-to-one name="Education" column="DIC_EDUCATION" not-null="false" class="DomainModel.ERP.Item,DomainModel" />
<many-to-one name="JobType" column="DIC_JOB_TYPE" not-null="false" class="DomainModel.ERP.Item,DomainModel" />
<set name="Addresses" table="TBL_ADDRESS" generic="true">
<key column="FK_EMPLOYEE" />
<one-to-many class="DomainModel.ERP.HRM.Address,DomainModel"/>
</set>
<property name="ItemCode" column="ITEM_CODE" type="integer" not-null="true"/>
<property name="DictCode" column="TABLE_CODE" type="integer" not-null="true"/>
<property name="Description" column="NAME" type="string" length="200" not-null="true"/>
<version name="Version" column="VERSION" type="integer" unsaved-value="0"/>
<property name="Description" column="DESCRIPTION" type="string" length="1000" not-null="false"/>
<property name="District" column="DISTRICT" type="string" length="15" not-null="false"/>
<property name="Community" column="COMMUNITY" type="string" length="150" not-null="false"/>
<property name="City" column="CITY" type="string" length="150" not-null="true"/>
<property name="Street" column="STREET" type="string" length="150" not-null="true"/>
<property name="PostalCode" column="POSTAL_CODE" type="string" length="10" not-null="false"/>
<property name="HouseNo" column="HOUSENO" type="string" length="20" not-null="true"/>
<property name="FlatNo" column="FLATNO" type="string" length="20" not-null="false"/>
<property name="Official" column="IS_OFFICIAL" type="Boolean" not-null="true"/>
<many-to-one name="Country" column="DIC_COUNTRY" not-null="false" class="DomainModel.ERP.Item,DomainModel" />
<many-to-one name="Region" column="DIC_REGION" not-null="false" class="DomainModel.ERP.Item,DomainModel" />
我需要:
- Retrive数据到我的网格控制
-
- 姓,
-
- 姓氏,
-
- NIP,
-
- 位置。说明,
-
- Education.Description,
-
- JobType.Description,
-
- Country.Description - 从地址,其中Address.Official是真实的,
-
- 街 - 从地址,其中Address.Official是真的,
-
- 的HouseNo - 从地址,其中Address.Official是真实的,
-
- FlatNo - 从地址,其中Address.O真实的。
- Retrive数据到另一个网格控制
-
- 姓,
-
- 名字,
-
- NIP,
-
- Position.Description ,
-
- Education.Description,
-
- JobType.Description。
和最重要的想法。我只想使用一个SELECT语句来完成此操作。 现在为第1点我使用NamedSQLQuery和一切正在工作的炉排,但对于最简单的情况我想使用CriteriaAPI。
也用于点1和2 I具有DTO类和我变换查询的结果到这个类。
我能做到这一点通过GetAllEmployees(),但许多属性是延迟加载,做我有应用程序和数据库之间的巨大TRAFIC。我可以将这些属性更改为Eager Loading,但在我看来,有太多的数据需要修改,我不需要。要显示与来自多个实体的数据网格,只需创建一个SQL视图和地图与NH -
您将需要包括你的映射一些细节给予任何形式的回答 – 2010-05-26 23:15:24
的你真的* *想要得到唯一的名字?通常当使用ORM时,你会得到整个对象。 – 2010-05-27 04:51:57