使用NSNumberFormatter格式化十进制数字

Question

您好，我需要格式化用户在应用程序中输入的十进制数字。

100. = 100 
90.00 = 90 
90.1 = 90.1 
90.22 = 90.22 
90.227 = 90.23 

我应该如何使用NSNumberFormatter来实现这一点。

我取得相同的，如果其他条件

if ([cell.textField.text rangeOfString:@"."].location != NSNotFound) 
    { 
     NSString *strAfterDecimal = [cell.textField.text componentsSeparatedByString:@"."].lastObject; 
     NSInteger count = [strAfterDecimal length]; 

     if(count == 0) 
     { 
      customField.value = [cell.textField.text 
           stringByReplacingOccurrencesOfString:@"." withString:@""]; 
     } 
     else if(count == 1 || count == 2) 
     { 
      if([strAfterDecimal integerValue] > 0) 
      { 
       customField.value = cell.textField.text; 
      } 
      else 
      { 
       customField.value = [cell.textField.text componentsSeparatedByString:@"."].firstObject; 
      } 
     } 
     else if(count > 2) 
     { 
      if([strAfterDecimal integerValue] > 0) 
      { 
       customField.value = [NSString stringWithFormat:@"%0.2f",[cell.textField.text floatValue]]; 
      } 
      else 
      { 
       customField.value = [cell.textField.text componentsSeparatedByString:@"."].firstObject; 
      } 
     } 
    } 

我需要consize的代码中使用这个自定义。至于根据客户我不能把额外的代码，如果苹果给出的默认功能做的事情

Answer 1

这是非常简单的

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; 
formatter.maximumFractionDigits = 2; 
NSNumber *number = [formatter numberFromString:cell.textField.text]; 
NSString *numberString = [formatter stringFromNumber:number]; 
if (numberString == nil) numberString = @"0"; 
NSLog(@"%@", numberString); 

雨燕的版本是一个比较复杂一点，因为你必须安全地解开了自选

let formatter = NumberFormatter() 
formatter.maximumFractionDigits = 2 
let numberString : String 
if let text = cell.textField.text, 
    let number = formatter.number(from: text), 
    let string = formatter.string(from: number) { 
    numberString = string 
} else { 
    numberString = "0" 
} 
print(numberString)