2014-10-09 98 views
0

在我的旅行网站(就像制作的Airbnb)多个领域的数据进行排序,用户可以在那里JSON(人民币),价格,位置等记录......我们可以使用JavaScript

我的网站数据(记录)格式only.I无法从数据库中获取记录。

个人资料记录:

var json = [ 
     {"id":"1","tagName":"apple",'lat':"37.764121333563985","lng":"-122.43083545083414",'cat':'bus','price':50}, 
     {"id":"2","tagName":"orange",'lat':"37.760390258066806","lng":"-122.40842161915589",'cat':'bus','price':50}, 
     {"id":"3","tagName":"banana",'lat':"37.76821074033546","lng":"-122.39946165364097",'cat':'car','price':70}, 
     {"id":"4","tagName":"watermelon",'lat':"37.76903501995947","lng":"-122.43674595206681",'cat':'bus','price':50}, 
     {"id":"5","tagName":"pineapple",'lat':"37.775329253488984","lng":"-122.42896304538613",'cat':'car','price':50}, 
     {"id":"6","tagName":"pineapple",'lat':"37.76808825514635","lng":"-122.42957791610439",'cat':'bus','price':30}, 
     {"id":"7","tagName":"pineapple",'lat':"37.764609542480706","lng":"-122.43126917941493",'cat':'bus','price':50}, 
     {"id":"8","tagName":"pineapple",'lat':"37.77486256468261","lng":"-122.40143099838457",'cat':'car','price':20}, 
     {"id":"9","tagName":"pineapple",'lat':"37.770304718740945","lng":"-122.42489358892846",'cat':'bus','price':50}, 
     {"id":"10","tagName":"pineapple",'lat':"37.7628338732316","lng":"-122.42631843030665",'cat':'car','price':10} 
    ]; 

我的JavaScript代码:

$(json).each(function(i,marker){ 
    if (cat == marker.cat || price <= marker.price) || (price <= marker.price && cat == marker.cat){ 
    var content = 'MY DATA CONTENT USING MARKER'; 
    $('.result').append(content); 
    } 
}); 

我如果条件不工作。

任何人都可以帮忙吗?

+1

这是我还是有一些遗漏的括号? – Falydoor 2014-10-09 07:44:50

+0

这是什么猫在这里javascript – 2014-10-09 07:44:51

+0

其我的分类 – 2014-10-09 07:46:47

回答

2

你如果condiition的括号都搞砸了,试试这个:

if ((cat == marker.cat || price <= marker.price) || (price <= marker.price && cat == marker.cat)) 
0
$(json).each(function(i,marker){ 
    if (cat == marker.cat || price <= marker.price) || (price <= marker.price && cat == marker.cat){ 
    var content = 'MY DATA CONTENT USING MARKER'; 
    $('.result').append(content); 
    } 

在这段代码没有被定义猫的价值,你需要或者将其更改为

this.cat or json[i].cat 

来访问json值。

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