用新单词替换字符串中的字符

Question

我有一个字符串数组，并且想进行一些替换。例如：

my_strings = [['hi/hello world &'], ['hi/hello world'], ['it\90s the world'], ['hello world'], ['hello "world"']] 

new_strings = [['hi and hello world'], ['hi and hello world'], ["it's the world"], ['hello world'], ['hello world']] 

我如何可以替换/与和，删除&和\ 90，并删除“”周围的话，如果阵列中的一个字符串中包含这些字符？

Answer 1

可以看出在该职位：How to delete a character from a string using python?

你可以在你的整个阵列在一个循环中使用，例如，类似的东西

if "/" in my_string: 
    new_string = my_string.replace("/", "and") 

而且包括它。

Answer 2

首先，您应该创建一个dict对象来映射单词与它的替换。例如：

my_replacement_dict = { 
    "/": "and", 
    "&": "", # Empty string to remove the word 
    "\90": "", 
    "\"": "" 
} 

在你的清单，replace以上字典基础上的话然后迭代，以获得所需的列表：

my_list = [['hi/hello world &'], ['hi/hello world'], ['it\90s the world'], ['hello world'], ['hello "world"']] 
new_list = [] 

for sub_list in my_list: 
    # Fetch string at `0`th index of nested list 
    my_str = sub_list[0] 
    # iterate to get `key`, `value` from replacement dict 
    for key, value in my_replacement_dict.items(): 
     # replace `key` with `value` in the string 
     my_str = my_str.replace(key, value) 
    new_list.append([my_str]) # `[..]` to add string within the `list` 

的new_list最终内容将是：

>>> new_list 
[['hi and hello world '], ['hi and hello world'], ['its the world'], ['hello world'], ['hello world']]