我试图解决这个问题:我有一个从的AsyncTask扩展一个类,即执行一些HTTP方法是这样的:的AsyncTask没有回调接口
public class RESTManager extends AsyncTask<Object, Object, String>
{
public RESTManager(String url, MethodTypes myMethod,ICallbackHandler hndl, String restMethod)
{
initialize();
}
private String doGET()
{
}
private String doPOST()
{
}
@Override
protected String doInBackground(Object... params)
{
}
@Override
protected void onPostExecute(String result)
{
}
}
所以,从活动我这样做:
RESTManager webService = new WSManager(URL, MethodTypes.REGISTER, params, this, WSManager.GET_METHOD);
webService.execute();
然后活性接收在callbak方法的响应(因为活动实现该接口):
public void response(String response)
{
// some process
}
这工作正常,但我的问题是,我希望答案出现在一些函数相同的调用,然后该函数调用.execute方法,例如。
// This is a new class
public class MyWebServices()
{
public User getUser(int id)
{
User myUser;
RESTManager webService = new WSManager(URL, MethodTypes.REGISTER, params, this, WSManager.GET_METHOD);
webService.execute();
// BUT I WANT TO RETURN FROM HERE THE CALL FROM THE ACTIVITY....LIKE
return myUser;
}
}
因此,从活动,这将是:
MyWebServices myService = new MyWebServices();
User usr = myService.getUser(id);
希望已了解了我试图描述,谢谢!
使用Future对象。 – alphazero 2012-04-17 15:05:25
对不起,我的无知是什么,未来的目标是什么? – skabo 2012-04-17 15:14:04
不需要道歉。这是S.O. http://docs.oracle.com/javase/6/docs/api/java/util/concurrent/Future.html – alphazero 2012-04-17 15:17:45