2015-02-24 72 views
0

我想让Spring为我初始化一个bean。请注意,我对调度员(我认为)并不感兴趣,因为我不在意让Spring自己初始化Vaadin组件。Vaadin 7 + Spring:没有ContextLoaderListener注册?

这是我到目前为止有:

web.xml中:

<web-app 
    id="WebApp_ID" version="2.4" 
    xmlns="http://java.sun.com/xml/ns/j2ee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> 

    <context-param> 
    <param-name>contextConfigLocation</param-name> 
    <param-value>classpath*:spring-context.xml</param-value> 
    </context-param> 

    <listener> 
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 
    </listener> 

    <servlet> 
    <servlet-name>TAM</servlet-name> 
    <servlet-class>com.vaadin.server.VaadinServlet</servlet-class> 
    <init-param> 
     <param-name>application</param-name> 
     <param-value>com.sgss.tam.web.MainUI</param-value> 
    </init-param> 
    <load-on-startup>1</load-on-startup> 
    </servlet> 

    <servlet-mapping> 
    <servlet-name>TAM</servlet-name> 
    <url-pattern>/tam/*</url-pattern> 
    </servlet-mapping> 
</web-app> 

弹簧的context.xml:

<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:jaxrs="http://cxf.apache.org/jaxrs" 
    xsi:schemaLocation=" 
     http://www.springframework.org/schema/beans 
     http://www.springframework.org/schema/beans/spring-beans-3.0.xsd 
     http://www.springframework.org/schema/context 
     http://www.springframework.org/schema/context/spring-context-3.0.xsd 
     http://cxf.apache.org/jaxrs 
     http://cxf.apache.org/schemas/jaxrs.xsd 
    "> 

    <!-- Turn on AspectJ @Configurable support --> 
    <context:spring-configured /> 

    <context:component-scan base-package="com.sgss.tam" /> 

    <!-- Turn on @Autowired, @PostConstruct etc support --> 
    <bean 
    class="org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor" /> 
    <bean 
    class="org.springframework.context.annotation.CommonAnnotationBeanPostProcessor" /> 

    <bean id="envVars" class="com.sgss.tam.service.EnvironmentVars"> 
     <property name="workflowEngineUrl" value="fafafaf"></property> 
     <property name="userAuthenticationUrl" value="fofofo"></property> 
    </bean> 
</beans> 

这个练习的要点是只需要具有由Spring配置的com.sgss.tam.service.EnvironmentVars。如果能正常工作,那么我应该能够通过如此实施WebApplicationInitializer在我的UI子类来访问这个bean,:

@Override 
public void onStartup(final ServletContext servletContext) throws ServletException { 
    final ApplicationContext context = WebApplicationContextUtils.getRequiredWebApplicationContext(servletContext); 
    final EnvironmentVars envVars = context.getBean("envVars", EnvironmentVars.class); 
} 

但是...

相反,onStartup执行上面的代码时,这里是实际发生的事情:

2015-02-24 15:53:34.814:INFO:/:main: Spring WebApplicationInitializers detected on classpath: [[email protected]] 
2015-02-24 15:53:42.706:WARN:oeja.ServletContainerInitializersStarter:main: 
java.lang.IllegalStateException: No WebApplicationContext found: no ContextLoaderListener registered? 
    at org.springframework.web.context.support.WebApplicationContextUtils.getRequiredWebApplicationContext(WebApplicationContextUtils.java:90) 
    at com.sgss.tam.web.MainUI.onStartup(MainUI.java:69) 

就好像我没有在web.xml中定义一个监听器。

如果我将侦听器类更改为不存在的东西,则会看到相应的错误消息,通知我该类未找到,这说明此配置实际上正在被解析。那么为什么没有Spring的上下文呢?

在此先感谢!

回答

0

好,三天后,这里是我的解决方案:

首先,我抛弃赞成Vaadin 7风格的标注的web.xml中对我的UI子类,所以:

@WebServlet(initParams = { // 
     @WebInitParam(name = "contextConfigLocation", value = "/WEB-INF/applicationConfiguration.xml") // 
}, value = { "/tam/*", "/VAADIN/*" }, asyncSupported = true) 
@VaadinServletConfiguration(productionMode = false, ui = MainUI.class, widgetset = "com.sgss.AppWidgetSet") 
public static class Servlet extends VaadinServlet { 
} 

请注意,重要的不是我为“contextConfigLocation”init var的值所作的贡献...... Jetty会高兴地忽略此值并加载/WEB-INF/applicationConfiguration.xml。但它必须存在。 所以我重命名并移动了上面的spring-context.xml来对应这个。

然后,我在MainUI实施WebApplicationInitializer的:

@Override 
public void onStartup(final ServletContext servletContext) throws ServletException { 
    final ContextLoaderListener listener = servletContext.createListener(ContextLoaderListener.class); 
    listener.initWebApplicationContext(servletContext); 
    final ApplicationContext context = WebApplicationContextUtils.getRequiredWebApplicationContext(servletContext); 
    environmentVars = context.getBean("envVars", EnvironmentVars.class); 
} 

environmentVars是MainUI一个静态变量。

很简单吧?