如果x比y高3

Question

我正在做一个程序来做一个猜谜游戏;我需要能够让程序给出H或L的反馈，只有当一个数字高于3或小于3时。

这是我目前有

import random 
def game3(): 
    rndnumber = str(random.randint(0,9999)) #gets a number between 0-9999 
    while len(rndnumber) < 4: 
     rndnumber = '0'+ rndnumber # adds 0s incase the number is less then a 1000 
    print(rndnumber) #lets me know that the program generates the right type of number (remove this after testing) 
    feedback = 0 #adds a variable 
    for x in range(1,11): #makes a loop that runs for 10 times 
     print("Attempt",x) 
     attempt = input("Guess a number between 0-9999:")#gets the users guess 
     feedback = "" #makes a feedback variable 
     for y in range(4): #makes a loop that runs for 4 times 
      if attempt[y] == rndnumber[y]: #if attempt is the same then add a Y to the number 
       feedback += "Y" 
      elif attempt[y] < rndnumber[y]: 
       feedback += "L" 
      elif attempt[y] > rndnumber[y]: 
       feedback += "H" 
      else: 
       feedback += "N" 
     print(feedback) 
     if x == 10: 
      print("You Lose the correct answer was",rndnumber) 
     if feedback == "YYYY" and x > 1: 
      print("You win it took",x,"attempts.") 
      break; #stops the program 
     elif feedback == "YYYY": 
      print("You won on your first attempt!") 
      break; #stops the program 

Answer 1

您可以使用

if attempt == rndnumber + 3 or attempt == rndnumber - 3: 
    # Do something... 

Answer 2

If x is 3 higher than y

if x+3 == y: 
    #code 

the program give feedback only if a number is 3 higher than the random number or 3 less.

if x+3 == y or x-3 == y: 
    #give feedback 

来源：

http://anh.cs.luc.edu/python/hands-on/3.1/handsonHtml/ifstatements.html

Answer 3

在第10行中，您在变量尝试中保存了一个字符串。 然而，在第13行中，您将尝试用作字典。

您可能想要在此重新考虑您的整个方法。

编辑：

当然我也是在一个点上做了猜谜游戏。虽然我现在肯定会使用不同的方法，但我认为这可能对您有所帮助，并在您的Python 3代码中为自己的游戏构建您的需求。

import random 

print ("Hello! What is your name?") 
name = input() 
print ("Well,", name, ", I am thinking of a number between 1 and 100.\nTake a guess.") 
number = random.randint(1, 100) # create a number between 1 and 100 
guess = input() # read user's guess 
guess = int(guess) 
guessnumber = 1 # first try to guess the number 
guessed = False # number isn't guessed yet 
while guessed == False: 
    if (number == guess): 
     print ("Good job,", name + "! You guessed my number in",guessnumber, "guesses!") 
     guessed = True 
    elif (guess > number): 
     print ("Your guess is too high.") 
     guess = input("Take another guess: ") 
     guess = int(guess) 
     guessnumber+=1 
    else: 
     print ("Your guess is too low.") 
     guess = input("Take another guess: ") 
     guess = int(guess) 
     guessnumber+=1