如何访问React Native中父组件中的子组件值（在ListView中）

Question

我的应用程序有一个列表视图，用于呈现项目列表。

我的子组件的每点击触发状态值

{ selected: !this.state.selected } 

在图像的变化上面我选择了2个个子项目，我怎么可以访问我的父组件自己的价值？

例如，

Big Data: true 
IoT: true 

这是我的父母片段，Hosted on Github too

import InterestItem from './InterestItem'; 

class AddInterest extends Component { 

    componentWillMount() { 
    this.createDataSource(this.props); 
    } 

    componentWillReceiveProps(nextProps) { 
    this.createDataSource(nextProps); 
    } 

    createDataSource({ items }) { 
    const ds = new ListView.DataSource({ 
     rowHasChanged: (r1, r2) => r1 !== r2 
    }); 
    this.dataSource = ds.cloneWithRows(items); 
    } 

    //return arrays of event from events 
    renderRow(item) { 
    return <InterestItem item={item} icon={computer} />; 
    } 

    render() { 
    const { centerEverything, skeleton, container, textContainer, contentContainer, listViewContainer, 
     titleContainer, descContainer, title, desc, submitContainer, submitTitle } = styles; 
    return (
     <View style={[container]}> 
     <View style={[centerEverything, textContainer]}> 
      <View style={titleContainer}> 
      <Text style={[title]}>What kind of events are you interest in?</Text> 
      </View> 
      <View style={descContainer}> 
      <Text style={[desc]}>You'll see more events from the categories you choose.</Text> 
      </View> 
     </View> 

     <View style={[contentContainer]}> 
      <ListView 
      enableEmptySections 
      contentContainerStyle={listViewContainer} 
      dataSource={this.dataSource} 
      renderRow={this.renderRow} 
      /> 
     </View> 

     <View style={[centerEverything, {paddingBottom: 10}]}> 
      <View style={[centerEverything, submitContainer]}> 
      <Text style={submitTitle}>Submit</Text> 
      </View> 
     </View> 

     </View> 
    ) 
    } 
} 

这是我的孩子组成，Hosted on GitHub too

class InterestItem extends Component { 

    state = { 
    selected: false 
    } 

    render() { 
    const { skeleton, centerEverything, container, textStyle } = styles; 
    return(
     <TouchableWithoutFeedback onPress={() => this.setState({ selected: !this.state.selected })}> 
     <View style={[centerEverything, container, { backgroundColor: this.state.selected ? '#635eb4' : '#e7e7e7'}]}> 
      {this.props.icon} 
      <Text style={textStyle}>{this.props.item[0]}</Text> 
     </View> 
     </TouchableWithoutFeedback> 
    ) 
    } 
} 

在从@freesoul要求，这里的儿童实例（考虑到我有8个孩子）

Answer 1

上@自由灵魂的后续行动，我会做如下修改代码：

constructor(){ 
    this.state = { 
    //... 
     rowStates: {} // Holds the state for each row, identified by the uid property (I'm assuming it is unique, otherwise use some other value) 
    } 
    this.renderRow = this.renderRow.bind(this); 
    this.rowUpdated = this.rowUpdated.bind(this); 
} 
renderRow(item) { 
    // Adds a callback so that we know when an element has been pressed 
    return <InterestItem item={item} icon={computer} onPress={() => this.rowUpdated(item)}/>; 
} 

rowUpdated(item){ 
    let rowStates = {...this.state.rowStates}; // Make a copy of the object 
    rowStates[item.uid] = !rowStates[item.uid]; // If the item is not in the object, !undefined will be evaluated, which results in true, so the operation is safe 
    this.setState({rowStates}); 
} 

然后，你的孩子组件应该是这样的：

class InterestItem extends Component { 

    state = { 
    selected: false 
    } 

    render() { 
    const { skeleton, centerEverything, container, textStyle } = styles; 
    return(
     <TouchableWithoutFeedback onPress={() => {this.setState({ selected: !this.state.selected }); if(this.props.onPress) this.props.onPress(this.props.item)}}> 
     <View style={[centerEverything, container, { backgroundColor: this.state.selected ? '#635eb4' : '#e7e7e7'}]}> 
      {this.props.icon} 
      <Text style={textStyle}>{this.props.item[0]}</Text> 
     </View> 
     </TouchableWithoutFeedback> 
    ) 
    } 
} 

希望它帮助