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我有一个数据帧ř使用data.table切割含有2或更多个变量
df <- data.frame(time = c("2015-09-07 00:32:19", "2015-09-07 01:02:30", "2015-09-07 01:31:36", "2015-09-07 01:47:45",
"2015-09-07 02:00:17", "2015-09-07 02:07:30", "2015-09-07 03:39:41", "2015-09-07 04:04:21", "2015-09-07 04:04:21", "2015-09-07 04:04:22"),
inOut = c("IN", "OUT", "IN", "IN", "IN", "IN", "IN", "OUT", "IN", "OUT"))
> df
time inOut
1 2015-09-07 00:32:19 IN
2 2015-09-07 01:02:30 OUT
3 2015-09-07 01:31:36 IN
4 2015-09-07 01:47:45 IN
5 2015-09-07 02:00:17 IN
6 2015-09-07 02:07:30 IN
7 2015-09-07 03:39:41 IN
8 2015-09-07 04:04:21 OUT
9 2015-09-07 04:04:21 IN
10 2015-09-07 04:04:22 OUT
>
我想要计算计数IN/OUT每15分钟的数量, 我可以做修复时间间隔这通过创建另一个in_df,out_df,每15分钟剪切一次这些数据帧,然后将它合并到一起以获得我的结果。 outdf是我的预期结果。
in_df <- df[which(df$inOut== "IN"),]
out_df <- df[which(df$inOut== "OUT"),]
a <- data.frame(table(cut(as.POSIXct(in_df$time), breaks="15 mins")))
b <- data.frame(table(cut(as.POSIXct(out_df$time), breaks="15 mins")))
colnames(b) <- c("Time", "Out")
colnames(a) <- c("Time", "In")
outdf <- merge(a,b, all=TRUE)
outdf[is.na(outdf)] <- 0
> outdf
Time In Out
1 2015-09-07 00:32:00 1 0
2 2015-09-07 00:47:00 0 0
3 2015-09-07 01:02:00 0 1
4 2015-09-07 01:17:00 1 0
5 2015-09-07 01:32:00 0 0
6 2015-09-07 01:47:00 2 0
7 2015-09-07 02:02:00 1 0
8 2015-09-07 02:17:00 0 0
9 2015-09-07 02:32:00 0 0
10 2015-09-07 02:47:00 0 0
11 2015-09-07 03:02:00 0 0
12 2015-09-07 03:17:00 0 0
13 2015-09-07 03:32:00 1 0
14 2015-09-07 03:47:00 0 0
15 2015-09-07 04:02:00 1 2
我的问题是如何用data.table做到这一点,以获得相同的结果?
用'.EACHI'好方法# – akrun
@Frank,谢谢,你的data.table sol非常好,很清楚,我将这个标记为答案,并为“dplyr”Sol创建另一个问题。 –
@JamesChen好吧,够公平的。我也有兴趣看看那些人也有这个想法。我不知道dplyr如何从'table'结果创建多个列。 – Frank