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我正在编写一个应用程序小部件,它从服务器获取数据并将它们显示在appwidget中。 的问题是,在没有互联网连接,在这一点上,系统更新微件,TextView
文本值复位与android:text="sometext"
将appwidget导致设置值更新为默认值
它发生这样的设置好的默认的文本:
- 的Widget放在主屏幕
- 互联网连接是活跃
- 的Widget成功更新
- 来自服务器的响应的文本安装在
TextView
- 互联网连接不活跃
- 系统更新微件的
TextView
重置为在android:text=""
设置好的,我知道在某个地方我做的并不正确的东西的价值
文件WidgetProvider.java
public class WidgetProvider extends AppWidgetProvider {
public static String LOG_TAG = "MYAPPLOG";
@Override
public void onReceive(Context context, Intent intent) {
super.onReceive(context, intent);
Log.d(LOG_TAG, "onReceive");
}
@Override
public void onUpdate(Context context, AppWidgetManager appWidgetManager, int[] appWidgetIds) {
super.onUpdate(context, appWidgetManager, appWidgetIds);
Log.d(LOG_TAG, "onUpdate");
for (int widgetID : appWidgetIds)
{
updateWidget(context, widgetID);
}
}
@Override
public void onDeleted(Context context, int[] appWidgetIds) {
super.onDeleted(context, appWidgetIds);
Log.d(LOG_TAG, "onDeleted");
}
public void updateWidget(Context context, int widgetID)
{
context.startService(new Intent(context, UpdatingService.class).putExtra(AppWidgetManager.EXTRA_APPWIDGET_ID, widgetID));
}
}
文件UpdatingService.java
public class UpdatingService extends IntentService {
public static String LOG_TAG = "MYAPPLOG";
public UpdatingService() {
super("UpdatingService");
}
@Override
protected void onHandleIntent(Intent intent) {
// getting widgetID from intent and other vars
RemoteViews remoteViews = new RemoteViews(getApplicationContext().getPackageName(),
R.layout.initial_layout);
if(isConnected(getApplicationContext()))
{
String response = getServerResponse();
if(response != null)
{
try {
JSONObject JSON = new JSONObject(response);
// get data from server
// ...
// set values to the views
remoteViews.setTextViewText(R.id.textView, someText);
} catch (JSONException e) {
e.printStackTrace();
Log.d(LOG_TAG, "JSONObject failed");
}
}
else
{
// LOG: error connection to server
}
}
else
{
// LOG: No internet connection
}
// updating apwidget (set click action for the some button)
// if not do update then button will not work
Intent someIntent = new Intent(getApplicationContext(), WidgetProvider.class);
someIntent.setAction(WidgetProvider.ACTION_GOTO);
PendingIntent pendingIntent = PendingIntent.getBroadcast(getApplicationContext(),
widgetID, someIntent, PendingIntent.FLAG_UPDATE_CURRENT);
remoteViews.setOnClickPendingIntent(R.id.goToLayout, pendingIntent);
AppWidgetManager.getInstance(getApplicationContext().getApplicationContext())
.updateAppWidget(widgetID, remoteViews);
}
public boolean isConnected(Context context) {
ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo ni = cm.getActiveNetworkInfo();
if (ni != null && ni.isConnected()) {
return true;
}
return false;
}
public String getServerResponse() {
// using HttpURLConnection
}
}
希望对您有所帮助或稍尖。我写了几个小部件,都有这个问题。非常感谢您的关注。
好吧,我在启动将属性设置为textview但仍不起作用的服务代码之前,粘贴了'updateWidget(Context context,int widgetID)'。每当系统更新没有互联网连接的小部件时,即使这些值是由前一次的服务设置的,它也会从xml中设置值。 –
您正在服务中创建应用程序小部件的UI,即RemoteViews remoteViews = new RemoteViews(getApplicationContext()。getPackageName(), R.layout.initial_layout);'。这是“重置”UI的代码。所以,不要更新'updateWidget(Context context,int widgetID)'方法,而是用'// LOG:没有互联网连接'来更新'Service'中的ELSE分支。在那里,您将设置应用程序小部件的文本为您保存的值。 – shelll
可能我只需要在一个服务中创建UI('RemoteViews remoteViews = new RemoteViews'),只能使用这个'remoteViews'(当我需要'remoteViews'时不要创建一个)? –