如何将多级索引DataFrame转换为乳胶表（Pandas-Jupyter）？

Question

考虑多级索引数据帧小号

import numpy as np 
import pandas as pd 
arrays = [['bar', 'bar', 'baz', 'baz', 'foo', 'foo', 'qux', 'qux'], 
    ...:   ['one', 'two', 'one', 'two', 'one', 'two', 'one', 'two']] 
tuples = list(zip(*arrays)) 
index = pd.MultiIndex.from_tuples(tuples, names=['first', 'second']) 
s = pd.DataFrame(np.random.randn(8, 4), index=arrays) 
s 

我如何可以将其转换为一个不错的表在使用python代码乳胶？

我试图

print s.to_latex() 

但失败了，给了我这样的结果

File "<ipython-input-45-d2f4611ecc13>", line 1 
    print s.to_latex() 
     ^
SyntaxError: invalid syntax 

我也试过

s.to_latex() 

，结果是不是在所有

'\\begin{tabular}{llrrrr}\n\\toprule\n &  &   0 &   1 &   2 &   3 \\\\\n\\midrule\nbar & one & -0.008518 & -0.535653 & -0.603135 & 0.891277 \\\\\n & two & 0.191005 & -1.470384 & 0.697245 & 1.054424 \\\\\nbaz & one & 0.414505 & -0.312967 & 0.703490 & 0.933851 \\\\\n & two & -0.295505 & -0.923843 & -0.423998 & 0.160162 \\\\\nfoo & one & -1.339702 & 0.616059 & 0.519983 & 0.554584 \\\\\n & two & -1.003784 & 0.674981 & 1.609906 & 0.274486 \\\\\nqux & one & -0.139274 & -0.783004 & 1.084794 & 2.202673 \\\\\n & two & -0.730785 & -0.468041 & 0.762726 & -0.532599 \\\\\n\\bottomrule\n\\end{tabular}\n' 

举办

Answer 1

你期望得到什么？这看起来是正确的，我...

import numpy as np 
import pandas as pd 
arrays = [['bar', 'bar', 'baz', 'baz', 'foo', 'foo', 'qux', 'qux'],['one', 'two', 'one', 'two', 'one', 'two', 'one', 'two']] 
tuples = list(zip(*arrays)) 
index = pd.MultiIndex.from_tuples(tuples, names=['first', 'second']) 
s = pd.DataFrame(np.random.randn(8, 4), index=arrays) 
s.to_latex() 

u'\\begin{tabular}{llrrrr}\n\\toprule\n &  &   0 &   1 &   2 &   3 \\\\\n\\midrule\nbar & one & -0.792068 & 1.667280 & 0.996496 & 0.278456 \\\\\n & two & -0.558638 & 0.329949 & -0.051455 & 0.586003 \\\\\nbaz & one & 0.400601 & -0.371393 & 1.041784 & -0.956686 \\\\\n & two & -0.007604 & -1.332577 & -1.010781 & -0.448133 \\\\\nfoo & one & 0.567487 & -0.929883 & 0.022723 & 0.945251 \\\\\n & two & 0.009925 & 0.556380 & 0.038697 & 0.067532 \\\\\nqux & one & -1.518476 & -1.706236 & 0.598467 & 1.439247 \\\\\n & two & 0.644754 & 0.929502 & 0.327730 & 0.557668 \\\\\n\\bottomrule\n\\end{tabular}\n'