SQL Query有什么问题？

Question

我能做些什么来解决这个SQL查询？

$q = $db->sqlQuery("SELECT * FROM project WHERE email = " . $email . ""); 

Answer 1

你可以试试这个：

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '" . $email . "'"); 

它缺少的单引号'应封闭$email值，因为它是一个字符串。

Answer 2

 
$q = $db->sqlQuery("SELECT * FROM project WHERE email = '" . $email . "'"); 

Answer 3

逃离参数。

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '" . $email . "'"); 

Answer 4

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '$email'"); 

Answer 5

$q = $db->sqlQuery("SELECT * FROM project WHERE email = '" . $email . "'"); 

您需要使用 '' 字符串变量

错误：SELECT * FROM project WHERE email = email@email.email

确定：SELECT * FROM project WHERE email = 'email@email.email'