这里是我的PHP代码PHP JSON响应
function GetTransactionList($data)
{
// DB transaction
$records = array();
while($row = mysql_fetch_array($result))
array_push($records, $row);
echo json_encode(array("IsError" => false, "Records" => $records));
}
这是从PHP
{
IsError:false,
Records:[
{0:1,
1:1000,
2:0,
3:"Peacock India trial payment",
4:"2013-08-03",
5:1,
TransactionID:1,
Credit:1000,
Debit:0,
Reason:"Peacock India trial payment",
TransactionDate:"2013-08-03",
TransactionByUserID:1
}]
}
在这里我得到了我的结果,但json_encode在Ajax调用我的JSON响应()方法先对每行进行两次编码,然后按index =>值对设置值,第二次按column_name =>值对进行编码。我想知道它为什么会发生?有什么办法可以减少这种双重工作。我想只有如下方式
{
IsError:false,
Records:[
{TransactionID:1,
Credit:1000,
Debit:0,
Reason:"Peacock India trial payment",
TransactionDate:"2013-08-03",
TransactionByUserID:1
}]
}
根据[mySQL mysql_fetch_array文档](http://php.net/manual/en/function),仅供参考,选项为** MYSQL_ASSOC **,** MYSQL_NUM **和** MYSQL_BOTH ** .mysql取入array.php) – DevlshOne