获取单选按钮的值设置

Question

我设置了响应由单选按钮标记处理选择题调查问卷A，B，C和D.

我想找出答案，每个通过获取表单ID和单击的按钮值来提出问题，例如，使用第一组单选按钮的响应可能是1B和第二，2D等等（表单ID脚本已经启动并运行）。

我需要这与多组单选按钮

这里的页面上工作是HTML：

<form class="toeic_pages" id="1"> 
     <label class="item1"> 
     <input type="radio" value="A" name="toeic"/> 
     <div class="radio-image"></div> 
     </label> 
     <label class="item2"> 
     <input type="radio" value="B" name="toeic"/> 
     <div class="radio-image"></div> 
     </label> 
     <label class="item3"> 
     <input type="radio" value="C" name="toeic"/> 
     <div class="radio-image"></div> 
     </label> 
     <label class="item4"> 
     <input type="radio" value="D" name="toeic"/> 
     <div class="radio-image"></div> 
     </label> 
    </form> 
    ...                 
    <form class="toeic_pages" id="2"> 
     <label class="item1"> 
     <input type="radio" value="A" name="toeic"/> 
     <div class="radio-image"></div> 
     </label> 
     <label class="item2"> 
     <input type="radio" value="B" name="toeic"/> 
     <div class="radio-image"></div> 
     </label> 
     <label class="item3"> 
     <input type="radio" value="C" name="toeic"/> 
     <div class="radio-image"></div> 
     </label> 
     <label class="item4"> 
     <input type="radio" value="D" name="toeic"/> 
     <div class="radio-image"></div> 
     </label> 
    </form> 

不过，虽然我已经能够用得到检查单选按钮值这个：

jQuery('input[name=toeic]').change(function(){ 
     var invar = jQuery('input[name=toeic]:checked').val(); 
     alert(invar); 
    }); 

该脚本只在点击的第一行按钮内有效。

为了说明，如果在要访问的第一行按钮中点击按钮B，则显示B（正确）。

但是，如果在另一行中，点击了按钮C，则B显示（不正确）..并且B继续显示以用于所有后续的按钮点击。我已经检查了这个SO网页，但我一直没有找到解决方案 - 这个问题似乎是多套单选按钮。

任何帮助将非常赞赏

Answer 1

你可以做这样的事情：

$(document).ready(function() { 
 
    $("#finish").click(function() { 
 
    var answersList = []; 
 
    //Loop over all questoins 
 
    $(".toeic_pages").each(function() { 
 

 
     var questionId = $(this).attr("id"); 
 
     var answer = $("input[name='toeic']:checked", $(this)).val(); 
 

 
     //if Answer isnt provided do not update the answersList 
 
     if (answer !== undefined) { 
 
     answersList.push({ 
 
      question: questionId, 
 
      answer: answer 
 
     }); 
 
     } 
 
    }); 
 
    console.log(answersList); 
 
    }); 
 
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<form class="toeic_pages" id="1"> 
 
    <label class="item1"> 
 
    <input type="radio" value="A" name="toeic" /> 
 
    <div class="radio-image"></div> 
 
    </label> 
 
    <label class="item2"> 
 
    <input type="radio" value="B" name="toeic" /> 
 
    <div class="radio-image"></div> 
 
    </label> 
 
    <label class="item3"> 
 
    <input type="radio" value="C" name="toeic" /> 
 
    <div class="radio-image"></div> 
 
    </label> 
 
    <label class="item4"> 
 
    <input type="radio" value="D" name="toeic" /> 
 
    <div class="radio-image"></div> 
 
    </label> 
 
</form> 
 
... 
 
<form class="toeic_pages" id="2"> 
 
    <label class="item1"> 
 
    <input type="radio" value="A" name="toeic" /> 
 
    <div class="radio-image"></div> 
 
    </label> 
 
    <label class="item2"> 
 
    <input type="radio" value="B" name="toeic" /> 
 
    <div class="radio-image"></div> 
 
    </label> 
 
    <label class="item3"> 
 
    <input type="radio" value="C" name="toeic" /> 
 
    <div class="radio-image"></div> 
 
    </label> 
 
    <label class="item4"> 
 
    <input type="radio" value="D" name="toeic" /> 
 
    <div class="radio-image"></div> 
 
    </label> 
 
</form> 
 

 
<button id="finish">Get Answers</button>

Answer 2

我认为这正是你需要的。

$('#1 input').on('change', function() { 
 
     alert($('#1').attr('id')+$('input[name=radioName]:checked', '#1').val()); 
 
    }); 
 
    $('#2 input').on('change', function() { 
 
     alert($('#2').attr('id')+$('input[name=radioName]:checked', '#2').val()); 
 
    }); 
 
    $('#3 input').on('change', function() { 
 
     alert($('#3').attr('id')+$('input[name=radioName]:checked', '#3').val()); 
 
    }); 
 
    $('#4 input').on('change', function() { 
 
     alert($('#4').attr('id')+$('input[name=radioName]:checked', '#4').val()); 
 
    });

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
    <form id="1"> 
 
    Question 1 
 
    <br> 
 
    <input type="radio" name="radioName" value="A" /> A <br /> 
 
    <input type="radio" name="radioName" value="B" /> B <br /> 
 
    <input type="radio" name="radioName" value="C" /> C <br /> 
 
    </form> 
 
    <form id="2"> 
 
     Question 2 
 
     <br> 
 
    <input type="radio" name="radioName" value="A" /> A <br /> 
 
    <input type="radio" name="radioName" value="B" /> B <br /> 
 
    <input type="radio" name="radioName" value="C" /> C <br /> 
 
    </form> 
 
    <form id="3"> 
 
     Question 3 
 
     <br> 
 
    <input type="radio" name="radioName" value="A" /> A <br /> 
 
    <input type="radio" name="radioName" value="B" /> B <br /> 
 
    <input type="radio" name="radioName" value="C" /> C <br /> 
 
    </form> 
 
    <form id="4"> 
 
     Question 4 
 
     <br> 
 
    <input type="radio" name="radioName" value="A" /> A <br /> 
 
    <input type="radio" name="radioName" value="B" /> B <br /> 
 
    <input type="radio" name="radioName" value="C" /> C <br /> 
 
    </form>

学分这个答案@Peter j的业主在这个问题上How can I know which radio button is selected via jQuery?