如何单独打印列表而不是合并它们？

的data，dic和abst是列表，在形式的数据：[[0, 1, 0, 0 , 1...0],[1, 0, 0, 1, 0, 1....0]]，在循环之后，我得到的结果是这样的：如何单独打印列表而不是合并它们？

abst = ['PS50802', 'PS50803', 'PS50804', 'PS50805', 'PS50806', 'PS50807', 'PS50808', 'PS50809', 'PS50810', 'PS50811', 'PS50812', 'PS50813', 'PS50814',......]

dic = ['PS50102' 'PS50101' 'PS50106' 'PS50199' 'PS50196' 'PS00832' 'PS50072'...]

[0.0， 0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0， 0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0， 0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，1.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0， 0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,1.0,0.0,0.0]

看起来像两个单独的列表合并成一个列表，但是怎么可以我得到的结果是这样的：

[0.0，0.0，0.0，0.0，0.0，0.0，1.0，0.0，0.0，0.0，0.0，0.0，0.0， 0.0，0.0，0.0，0.0， 0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，，[0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0，，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，0.0，1.0，0.0，0.0，0.0，0.0，0.0，0.0，1.0，0.0，0.0]]

lines = [] 

for x in range(0, 2): 
    for item in dic: 
     for i,j in enumerate(abst):  
      if item == j: 
       lines.append(data[x][i]) 

print lines

来源

2015-04-17 Kun

你能解决你的第二个结果？它缺少一个括号 –

你可以发布你的数据，dic和abst变量的简化版本，并确切地说明你想要实现的目标吗？ – CoMartel

@HarryPotfleur，是的，我做到了。 – Kun

如果您想保留两个列表的列表，你可以试试这个：

lines = [] 
for x in range(0, 2): 
    line = [] 
    for item in dic: 
     for i,j in enumerate(abst):  
      if item == j: 
       line.append(data[x][i]) 
    lines.append(line) 

print lines

，你也许能够简化

lines = [] 
for x in range(0, 2): 
    line = [] 
    for item in dic: 
     if item in abst: 
      i = abst.index(item) 
      line.append(data[x][i]) 
    lines.append(line)

或

lines = [] 
for x in range(0, 2): 
    line = [data[x][abst.index(item)] for item in dic if item in abst] 
    lines.append(line)

最后，用一个列表理解：

lines = [ [data[x][abst.index(item)] for item in dic if item in abst] for x in range(0, 2) ]

来源

2015-04-17 13:44:07

是的，这是我想要的，谢谢。 – Kun

不客气:-) –

如何单独打印列表而不是合并它们？

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