Laravel关系集合迭代返回布尔

我有一个递归关系（段和子段）定义为这ReportSection模式：Laravel关系集合迭代返回布尔

function sub_sections() { 
    return $this->hasMany('App\ReportSection', 'parent_id'); 
}

，我试图来遍历它，像这样：

$section = Section::find($id); 
     \DB::beginTransaction(); 
     try { 
      foreach(ReportForm::unlockedForm($section->form_id)->get() as $report) { 
      foreach($report->sections()->where('section_id', $section->id)->get() as $reportSections) { 
       \Log::info($reportSections); 
       foreach($reportSections as $rSection) { 
       \Log::info($rSection); 
       foreach($rSection->sub_sections as $subSection) {

线\Log::info($reportSections);给{"id":3,"report_form_id":1,"name_en":"DDD","name_fr":"DDD","created_at":"2016-11-29 07:47:24","updated_at":"2016-11-29 07:47:32","section_id":118,"parent_id":1,"order":99,"hidden":0}预期

，但通过它的迭代莫名其妙地给了一个布尔值\Log::info($rSection);给1

最后一行foreach($rSection->sub_sections as $subSection) {给出了错误'Trying to get property of non-object'

为什么会迭代通过关系集合给出一个布尔值？我究竟做错了什么？

编辑：改变sub_sections（）来sub_sections但错误仍然存在

来源

2016-11-29 Ave

你应该调用属性名称不是方法：

foreach($rSection->sub_sections as $subSection) 
{}

来源

2016-11-29 13:34:58

是啊，我现在认识到这一点，也许早就抓住了，但发生错误的事项之前，我没有进行更改， $ rSection仍然是1. – Ave

这里是一样的：'$ report-> sections-> where（'section_id'，$ section-> id） - > get（）' –

我想你必须把它称为一种方法查询 – Ave

好的休息一会我就能够弄清楚后问题是我正在迭代两次相同的集合。

而不是

foreach(ReportForm::unlockedForm($section->form_id)->get() as $report) { 
      foreach($report->sections()->where('section_id', $section->id)->get() as $reportSections) { 
       foreach($reportSections as $rSection) {

应该已经

foreach(ReportForm::unlockedForm($section->form_id)->get() as $report) { 
      foreach($report->sections()->where('section_id', $section->id)->get() as $rSection) {

来源

2016-11-29 17:06:46 Ave

Laravel关系集合迭代返回布尔

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