2016-06-08 138 views
4

当我有2种方法异常反序列化JSON

public static string SerializeObject<T>(T value) 
{ 
    if (value == null) 
    { 
     return null; 
    } 

    var dictionaryObject = new Dictionary<string, object> { { typeof(T).Name, value } }; 

    var jsonString = JsonConvert.SerializeObject(dictionaryObject); 

    return jsonString; 
} 

public static T DeserializeObject<T>(string jsonString) 
{ 
    var objectValue = JsonConvert.DeserializeObject<Dictionary<string, object>>(jsonString); 
    return JsonConvert.DeserializeObject<T>(objectValue.Values.First().ToString()); 
} 

当我反序列化JSON字符串类型

ConcurrentDictionary<KeyValuePair<long, long>, IList<string>> 

我有一个例外:

Co uld不会将字符串'[1,1]'转换为字典键类型'System.Collections.Generic.KeyValuePair`2 [System.Int64,System.Int64]'。创建一个TypeConverter将字符串转换为键类型对象。 Path'[1,1]',第2行,第12位。

所以有人可以让我看看它的正确工作方式吗?

这里是我的代码:

var test = new ConcurrentDictionary<KeyValuePair<long, long>, IList<string>>(); 
test.TryAdd(new KeyValuePair<long, long>(1, 1), new List<string> { "Test" }); 

var se = SerializeObject(test); 

var de = DeserializeObject<ConcurrentDictionary<KeyValuePair<long, long>, IList<string>>>(se); 
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为什么你把它变成一个字典? – Toxicable

+0

你可能需要更多地解释你想要完成的事情。不知道你想用Dictionary来解决什么问题。 – d512

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@ user1334007:我想反序列化一个JSON字符串到类型为ConcurrentDictionary的对象,IList > –

回答

3

我不知道这是否是最好的解决办法,但是,请试试这个:

1)在this topic描述创建ContractResolver。

class DictionaryAsArrayResolver : DefaultContractResolver 
     { 
      protected override JsonContract CreateContract(Type objectType) 
      { 
       if (objectType.GetInterfaces().Any(i => i == typeof(IDictionary) || 
        (i.IsGenericType && 
        i.GetGenericTypeDefinition() == typeof(IDictionary<,>)))) 
       { 
        return base.CreateArrayContract(objectType); 
       } 

       return base.CreateContract(objectType); 
      } 
     } 

2)改了一下你的序列化/反序列化方法:

public static string SerializeObject<T>(T value, JsonSerializerSettings settings) 
     { 
      if (value == null) 
      { 
       return null; 
      } 

      var dictionaryObject = new Dictionary<string, object> { { typeof(T).Name, value } }; 
      var jsonString = JsonConvert.SerializeObject(dictionaryObject, settings); 

      return jsonString; 
     } 

     public static T DeserializeObject<T>(string jsonString, JsonSerializerSettings settings) 
     { 
      var objectValue = JsonConvert.DeserializeObject<Dictionary<string, object>>(jsonString, settings); 
      return JsonConvert.DeserializeObject<T>(objectValue.Values.First().ToString(), settings); 
     } 

3)检查测试:

[TestMethod] 
     public void Test() 
     { 
      var test = new ConcurrentDictionary<KeyValuePair<long, long>, IList<string>>(); 
      test.TryAdd(new KeyValuePair<long, long>(1, 1), new List<string> { "Test" }); 

      JsonSerializerSettings settings = new JsonSerializerSettings(); 
      settings.ContractResolver = new DictionaryAsArrayResolver(); 

      var se = SerializeObject(test, settings); 

      var de = DeserializeObject<ConcurrentDictionary<KeyValuePair<long, long>, IList<string>>>(se, settings); 
     } 

我希望它有助于=)

+0

它的工作,感谢您的解决方案:) @Johnny Svarog –

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不用客气=) –