我现在有最奇怪的问题。为了查看联系人是否已经在数据库中,我检查它。对我来说,我会回应:“在数据库中”或“不在数据库中”。为了让使用者看到我用同样的按摩给他回来了弦。奇怪的是,回声总是正确的,但字符串总是相同的“不在数据库中”,即使联系人在数据库中。例如:我添加我的妈妈。我的妈妈在数据库中,所以回声是正确的,并说“在数据库中”。但是我得到的字符串总是说“不在数据库中”。PHP文件返回正确的回声,但在数据库中写入错误的字符串
的完整代码
<?php
$DB_HostName = "localhost";
$DB_Name = "db";
$DB_User = "user";
$DB_Pass = "pw";
$DB_Table = "contacts";
$con = mysql_connect($DB_HostName,$DB_User,$DB_Pass) or die (mysql_error());
mysql_select_db($DB_Name,$con) or die(mysql_error());
$fnumber = mysql_real_escape_string($_GET["fnumber"]);
$result = mysql_query("SELECT * FROM $DB_Table WHERE User = '$fnumber'", $con);
if ($result) {
if (mysql_num_rows($result) > 0) {
echo "This user is already in database";
$number = mysql_real_escape_string($_GET["number"]);
mysql_query("DELETE FROM Echo WHERE Number=('$number')");
mysql_query("INSERT INTO Echo (Number,Answer)
VALUES ('$number','This user is already in database.')");
}
else echo
"This user isn't in the database";
$number = mysql_real_escape_string($_GET["number"]);
mysql_query("DELETE FROM Echo WHERE Number=('$number')");
mysql_query("INSERT INTO Echo (Number,Answer)
VALUES ('$number','this user isn't in the database.')");
}
mysql_close($con);
?>
而且你问之前:为了不挤我的数据库,我总是删除的号码,然后写的条目。
“你问之前:为了不挤我的数据库,我总是删除的号码,然后写的条目。” 您是否知道您可以更新现有行中的数据? – BenOfTheNorth 2012-02-27 14:29:19