2012-07-21 89 views
0

所以我一直在试图为客户编写一个CMS来更新他们的网站。我正在试图让更新新闻脚本起作用,并且我想知道如何让脚本不仅更新新闻本身,而且还更新标题。下面是该脚本:更新CMS上的新闻

PHP:

//used to get data from previous page. $previous_title was so I can use it to set the where in the update query. 
    if($_GET['title']) { 
      $title = $_GET['title']; 
      $previous_title = $_GET['title']; 
    } 
    if($_POST['title']) { 
      $title = $_POST['title']; 
      $news = $_POST['news']; 

      //used to update both news and title 
      mysql_query("UPDATE `News` SET `Title`='$title', `Content`='$news' WHERE `Title`='$previous_title'"); 
    header("Location: viewNews.php"); 
    } 

HTML:

   <form id = "addNews" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> 
       <input type="hidden" name="hidden" id="hidden" value="hidden" /> 
       <input type="text" name="title" size="68" id = "title" value="<?php echo $query['Title'];?>"/><br/><br/> 
       <textarea name="news" id="news"><?php echo $query['Content'];?></textarea><br /> 
       <input type="submit" value="Update News"/> 
       </form> 

谢谢!

回答

0

更新询问要更新这两个领域Title & Content

UPDATE `News` SET `Title`='$title', `Content`='$news' WHERE `Title`='$previous_title 

,但如果要更新,然后唯一的新闻您的SQL是这样的:

UPDATE `News` SET `Content`='$news' WHERE `Title`='$previous_title 

你应该好好$previous_title 因为护理在这种情况下$previous_title可能不可用

if($_POST['title']) { 
      $title = $_POST['title']; 
      $news = $_POST['news']; 

      mysql_query("UPDATE `News` SET `Title`='$title', `Content`='$news' WHERE `Title`='$previous_title'"); 
    header("Location: viewNews.php"); 
    } 
+0

会有更新标题和新闻的方法吗? – Andrew 2012-07-21 05:50:37