0
此代码适用于php 7
(本地主机),但不是php 5
(isp)。它将分隔文本文件转换为json
文件,以便与dataTables
一起使用。脚本在PHP 7中工作,但不是PHP 5
来源:
6590|07/19/2003|RCC Sat. Open|C11|Nikolayev, Igor (FM)|2402|Gonzalez, Jose|2131|1-0|
期望的结果:
{"data":[
{"game":"6624","Date":"11/01/2003","Event":"RCC Sat. Open","ECO":"C65","White":"Liman, Christ","WhiteElo":"1729","Black":"Nikolayev, Igor (FM)","BlackElo":"2408","Result":"0-1"},
....
]}
怎么来的?使用
<?php
$text = file('games.txt'); $count = count($text); arsort($text);
$X = 0;
$fp = fopen("games.json", "w");
fwrite ($fp, "{"); fwrite ($fp, '"data":[');
foreach($text as $line) {$token = explode("|", $line);
$game = $token[0]; $date = $token[1]; $event = $token[2]; $eco = $token[3]; $white = $token[4];
$white_rating = $token[5]; $black = $token[6]; $black_rating = $token[7]; $result = $token[8];
fwrite ($fp, "\n");
fwrite ($fp,'{');
fwrite ($fp, '"game":"'.$game.'",');
fwrite ($fp, '"Date":"'.$date.'",');
fwrite ($fp, '"Event":"'.$event.'",');
fwrite ($fp, '"ECO":"'.$eco.'",');
fwrite ($fp, '"White":"'.$white.'",');
fwrite ($fp, '"WhiteElo":"'.$white_rating.'",');
fwrite ($fp, '"Black":"'.$black.'",');
fwrite ($fp, '"BlackElo":"'.$black_rating.'",');
fwrite ($fp, '"Result":"'.$result.'"');
$X++;
fwrite ($fp, '}');
if ($X <= $count-1) {fwrite ($fp, ',');}
}
fwrite ($fp, "]");
fwrite ($fp, "}");
fclose($fp);
header('Location:pgn_assistant.php');
?>
当'json_encode'原生存在时,建议您自己创建JSON转换方法不可取。你也得到任何错误? – apokryfos
我没有收到任何错误。我将很快调查json_encode。 – verlager
从表面上看,我没有看到任何与PHP 5.6不兼容的东西。您的权限是否正确,正在尝试读取和写入的文件?或者他们在正确的位置? – thodic