我该如何让我的交换机回到主交换机？

Question

美好的一天......我正在创建一个地址簿程序......我在我的主菜单中使用了一个开关......并计划为我的编辑菜单创建另一个开关......我的问题是......我不'知道如何回到我的主开关...这是我的主要程序：

import javax.swing.JOptionPane; 
import javax.swing.JTextArea; 

public class AddressBook { 

    private AddressBookEntry entry[]; 
    private int counter; 

    public static void main(String[] args) { 
     AddressBook a = new AddressBook(); 
     a.entry = new AddressBookEntry[100]; 
     int option = 0; 
     while (option != 6) { 
      String content = "Choose an Option\n\n" 
        + "[1] Add an Entry\n" 
        + "[2] Delete an Entry\n" 
        + "[3] Update an Entry\n" 
        + "[4] View all Entries\n" 
        + "[5] View Specific Entry\n" 
        + "[6] Exit"; 
      option = Integer.parseInt(JOptionPane.showInputDialog(content)); 
      switch (option) { 
       case 1: 
        a.addEntry(); 
        break; 
       case 2: 

        break; 
       case 3: 
        a.editMenu(); 
        break; 
       case 4: 
        a.viewAll(); 
        break; 
       case 5: 
        break; 
       case 6: 
        System.exit(1); 
        break; 
       default: 
        JOptionPane.showMessageDialog(null, "Invalid Choice!"); 
      } 
     } 
    } 

    public void addEntry() { 
     entry[counter] = new AddressBookEntry(); 
     entry[counter].setName(JOptionPane.showInputDialog("Enter name: ")); 
     entry[counter].setAdd(JOptionPane.showInputDialog("Enter add: ")); 
     entry[counter].setPhoneNo(JOptionPane.showInputDialog("Enter Phone No.: ")); 
     entry[counter].setEmail(JOptionPane.showInputDialog("Enter E-mail: ")); 
     counter++; 
    } 

    public void viewAll() { 
     int i = 0; 
     for (; i < counter; i++) { 
      JOptionPane.showMessageDialog(null, new JTextArea(entry[i].getInfo())); 
     } 
    } 

    public void editMenu() { 
     int option = 0; 
     while (option != 6) { 
      String content = "Choose an Option\n\n" 
        + "[1] Edit Name\n" 
        + "[2] Edit Address\n" 
        + "[3] Edit Phone No.\n" 
        + "[4] Edit E-mail address\n" 
        + "[5] Go Back to Main Menu\n"; 
      option = Integer.parseInt(JOptionPane.showInputDialog(content)); 
      switch (option) { 
       case 1: 
        editEntry(); 
        break; 
       case 2: 
        break; 
       case 3: 
        break; 
       case 4: 
        break; 
       case 5: 
        break; 
       default: 
        JOptionPane.showMessageDialog(null, "Invalid Choice!"); 
      } 
     } 
    } 

    public void editEntry() { 
     String EName; 
     EName = JOptionPane.showInputDialog("Enter name to edit: "); 
     for (int i = 0; i < counter; i++) { 
      if (entry[i].getName().equals(EName)) { 
       entry[i].setName(JOptionPane.showInputDialog("Enter new name: ")); 
      } 
     } 
    } 
} 

请帮助...在此先感谢:)

Answer 1

要返回给调用者，可以使用return;代替break;

In editMenu

  case 5: 
       return; 

不过，我怀疑你的问题是，

while (option != 6) { 

应该

while (option != 5) { 

你也可以使用一个标签打出来的，而循环这将在这里做同样的事情的。