不用引用列表说下面的代码无法正常工作,故障或问题似乎是功能不访问或识别列表[卡]。另一方面,如果我将列表[卡片]放入函数中,则代码完美地工作。我假定放在主代码中的变量是全局变量,并且在函数中声明的变量只是局部变量。Python的 - 在功能
#!/usr/bin/python
import random
cards = ['A︎♣︎︎', '2︎♣︎︎', '3︎♣︎︎', '4︎♣︎︎', '5︎♣︎︎', '6︎♣︎︎', '7︎♣︎︎', '8︎♣︎︎', '9︎♣︎︎', '10︎♣︎︎', 'J︎♣︎︎', 'Q︎♣︎︎',
'K︎♣︎︎', 'A♠︎', '2♠︎', '3♠︎', '4♠︎', '5♠︎', '6♠︎', '7♠︎', '8♠︎', '9♠︎', '10♠︎', 'J♠︎',
'Q♠︎', 'K♠︎', 'A︎♥︎', '2︎♥︎', '3︎♥︎', '4︎♥︎', '5︎♥︎', '6︎♥︎', '7︎♥︎', '8︎♥︎', '9︎♥︎', '10︎♥︎',
'J︎♥︎', 'Q︎♥︎', 'K︎♥︎', 'A︎♦︎︎', '2︎♦︎︎', '3︎♦︎︎', '4︎♦︎︎', '5︎♦︎︎', '6︎♦︎︎', '7︎♦︎︎', '8︎♦︎︎', '9︎♦︎︎',
'10︎♦︎︎', 'J︎♦︎︎', 'Q︎♦︎︎', 'K︎♦︎︎']
# define function
def sort_cards(hand):
temp = []
for n in range(0, 7):
temp.append(cards.index(str(hand[n])))
# sort cards
temp.sort()
hand = []
# fetch card according to index and assign to hand
for c in temp:
hand.append(cards[c])
return hand
# copy cards list to working list
rem_cards = cards
# initiate players card list
player1 = []
player2 = []
player3 = []
# define variable
# 7 cards per player
deal = 7
while deal != 0:
# get a card from rem_cards and assign to player1
card = rem_cards[random.randint(0, len(rem_cards) - 1)]
player1.append(card)
# remove card from deck
rem_cards.remove(card)
card = rem_cards[random.randint(0, len(rem_cards) - 1)]
player2.append(card)
rem_cards.remove(card)
card = rem_cards[random.randint(0, len(rem_cards) - 1)]
player3.append(card)
rem_cards.remove(card)
deal -= 1
print(sort_cards(player1))
print(sort_cards(player2))
print(sort_cards(player3))
print("No of cards left in the deck is ", len(rem_cards))
任何建议或我的概念只是错了吗?
什么是“不行”是什么意思?你会得到一个错误或意外的输出? –
如果你希望在函数内部使用全局变量,你应该用'global'关键字在函数体中声明这个变量 –
只是一个提示:使用'random.choice'而不是'random.randint(0,len (rem_cards) - 1)' –