0
当用户点击UILocalNotification
时,我正尝试使用特定屏幕启动我的应用。这是我在AppDelegate
代码:iOS UILocalNotification启动特定屏幕
// MARK: - Local Notification
func application(_ application: UIApplication, didReceive notification: UILocalNotification)
{
if (application.applicationState == UIApplicationState.active)
{
print("Active")
}
else if (application.applicationState == UIApplicationState.background)
{
print("Background")
}
else if (application.applicationState == UIApplicationState.inactive)
{
print("Inactive")
print(notification.userInfo as Any)
self.redirectToPage(userInfo: notification.userInfo as! [String : String])
}
}
func redirectToPage(userInfo: [String : String]!)
{
if userInfo != nil
{
if let pageType = userInfo["TYPE"]
{
if pageType == "Page1"
{
let storyboard = UIStoryboard(name: "Main", bundle: nil)
self.window?.rootViewController = storyboard.instantiateViewController(withIdentifier: "promoVC")
}
}
}
}
它正常工作时,应用程序在后台或不活动状态,但是当它被暂停,攻丝UILocalNotification
默认屏幕启动应用程序。如何在特定屏幕处于暂停状态时启动我的应用程序?
当应用程序暂停时,通知正在被'didFinishLaunchingWithOptions'方法捕获。 – ridvankucuk