排除两天之间的假期

Question

大家好我正在开展一个关于计算特定工作日的项目。 我的条件是：周六不是假期，这是工作日。

我写了这个代码everyting是星期天只有okey跳过，但我想跳过，如果包含假期日期。

问题：跳过周日但不跳过传递的假期列表值。

将来的日期计算功能：

public DateTime CalculateFutureDate(DateTime fromDate, int numberofWorkDays, 
            List<DateTime> holidays) 
{ 
    var futureDate = fromDate; 
    for (var i = 0; i < numberofWorkDays; i++) 
    { 
     if (
      futureDate.DayOfWeek == DayOfWeek.Sunday 
      || (holidays != null && holidays.Contains(futureDate))) 
     { 
      futureDate = futureDate.AddDays(1); 
      numberofWorkDays++; 
     } 
     else 
     { 
      futureDate = futureDate.AddDays(1); 
     } 
    } 
    while (
      futureDate.DayOfWeek == DayOfWeek.Sunday 
      || (holidays != null && holidays.Contains(futureDate))) 
    { 
     futureDate = futureDate.AddDays(1); 
    } 

    return futureDate; 
} 

主要功能：

List<DateTime> holidayslist = new List<DateTime>(); 
holidayslist.Add(new DateTime(2016, 09, 7)); 
holidayslist.Add(new DateTime(2016, 09, 8)); 
holidayslist.Add(new DateTime(2016, 09, 9)); 
DateTime izinbaslangic = Convert.ToDateTime(dtpİzinBaslangicTarihi.Value, System.Globalization.CultureInfo.CreateSpecificCulture("tr-TR").DateTimeFormat); 
dtpİzinBitisTarihi.Value = CalculateFutureDate(izinbaslangic, Int32.Parse(tbİzinGunu.Text), holidayslist); 

输入：izinbaslangic - >的DateTimePicker值和workingdays - > tbizingunu值

期待输出：排除假日和周末在另一个datetimepicker显示新的日期。

输出：只跳过Weekends.Not跳过节假日。

期待输出图像：enter image description here

Answer 1

我将重写代码以下列方式

public DateTime CalculateFutureDate(DateTime fromDate, int numberofWorkDays, 
            List<DateTime> holidays) 
{ 
    var futureDate = fromDate; 
    while (numberofWorkDays != 0) 
    { 
     if (!isHoliday(futureDate, holidays)) 
      numberofWorkDays--; 
     futureDate = futureDate.AddDays(1); 
    } 
    while (isHoliday(futureDate, holidays)) 
     futureDate = futureDate.AddDays(1); 
    return futureDate; 
} 

bool isHoliday(DateTime testDate, List<DateTime>holidays) 
{ 
    return (testDate.DayOfWeek == DayOfWeek.Sunday 
      || (holidays != null && holidays.Contains(testDate.Date))); 
} 

的想法很简单，直到所需的工作日数减少到零，以创建一个循环。同时隔离逻辑来测试一个假期将有很大的帮助更好地理解代码，避免在同一逻辑的危险重复

List<DateTime> holidayslist = new List<DateTime>(); 
holidayslist.Add(new DateTime(2016, 09, 7)); 
holidayslist.Add(new DateTime(2016, 09, 8)); 
holidayslist.Add(new DateTime(2016, 09, 9)); 

DateTime start = new DateTime(2016,9,7); 
DateTime ending = CalculateFutureDate(start, 1, holidayslist); 
Console.WriteLine(ending.ToString()); // 12/09/2016 00:00:00