谷歌融合表中多个点的地理位置限制

Question

我试图在同一行中同时对这27个点进行地理定位。但是该过程仅返回前10个点，即使在预览中它们全部都是正确定位的。为什么？对于我可以找到的点数有没有特别的限制？

<Point><coordinates>7.680237,45.064504,0.0</coordinates></Point> 
<Point><coordinates>7.681675,45.061957,0.0</coordinates></Point> 
<Point><coordinates>7.685044,45.060768,0.0</coordinates></Point> 
<Point><coordinates>7.686482,45.06029,0.0</coordinates></Point> 
<Point><coordinates>7.689443,45.05926,0.0</coordinates></Point> 
<Point><coordinates>7.692157,45.060836,0.0</coordinates></Point> 
<Point><coordinates>7.693799,45.062837,0.0</coordinates></Point> 
<Point><coordinates>7.69352,45.06605,0.0</coordinates></Point> 
<Point><coordinates>7.693316,45.065519,0.0</coordinates></Point> 
<Point><coordinates>7.693723,45.065193,0.0</coordinates></Point> 
<Point><coordinates>7.694796,45.069065,0.0</coordinates></Point> 
<Point><coordinates>7.689893,45.072081,0.0</coordinates></Point> 
<Point><coordinates>7.684025,45.075225,0.0</coordinates></Point> 
<Point><coordinates>7.682716,45.075377,0.0</coordinates></Point> 
<Point><coordinates>7.675881,45.078135,0.0</coordinates></Point> 
<Point><coordinates>7.674809,45.076672,0.0</coordinates></Point> 
<Point><coordinates>7.673264,45.074521,0.0</coordinates></Point> 
<Point><coordinates>7.672727,45.073809,0.0</coordinates></Point> 
<Point><coordinates>7.671729,45.072399,0.0</coordinates></Point> 
<Point><coordinates>7.670302,45.071013,0.0</coordinates></Point> 
<Point><coordinates>7.669648,45.070119,0.0</coordinates></Point> 
<Point><coordinates>7.669197,45.068565,0.0</coordinates></Point> 
<Point><coordinates>7.670592,45.06802,0.0</coordinates></Point> 
<Point><coordinates>7.672427,45.067414,0.0</coordinates></Point> 
<Point><coordinates>7.67557,45.065981,0.0</coordinates></Point> 
<Point><coordinates>7.675592,45.06633,0.0</coordinates></Point> 
<Point><coordinates>7.675892,45.064094,0.0</coordinates></Point> 

Answer 1

谷歌地图反向地理编码器（无论使用哪一个）都受配额和速率限制。如果您不检查并处理OVER_QUERY_LIMIT返回的状态，您将获得该行为。

对于只有10个最显眼的位置才显示的多个几何体，以前只有一个限制（尽管如此，在FusionTables的文档中找不到）。将每个点放在它自己的行中。