嘿,我一直在做一些改变,我的Django的农业开发ENV,因为你们中的一些建议Django的。 到目前为止,我已经设法配置并使用postgres成功运行它。错误使用Apache和mod_wsgi的
现在我试图运行应用程序使用apache2和mod_wsgi,但我遇到了这个小问题后,我遵循django文档的指导方针。
当我访问本地主机/ MYAPP /任务这个错误引发:
Request Method: GET
Request URL: http://localhost/myapp/tasks/
Exception Type: TemplateSyntaxError
Exception Value:
Caught an exception while rendering: argument 1 must be a string or unicode object
Original Traceback (most recent call last):
File "/usr/local/lib/python2.6/dist-packages/django/template/debug.py", line 71, in render_node
result = node.render(context)
File "/usr/local/lib/python2.6/dist-packages/django/template/defaulttags.py", line 126, in render
len_values = len(values)
File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 81, in __len__
self._result_cache = list(self.iterator())
File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 238, in iterator
for row in self.query.results_iter():
File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py", line 287, in results_iter
for rows in self.execute_sql(MULTI):
File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py", line 2369, in execute_sql
cursor.execute(sql, params)
File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 19, in execute
return self.cursor.execute(sql, params)
TypeError: argument 1 must be a string or unicode object
... ... ...
然后它{在任务%为T%}突出了一个模板标签,就像这个问题的根源在那里,但它在内置服务器上运行良好。
与该页面相关的视图是真的是简单,只需获取所有Task对象。模板只是将它们显示在一张桌子上。
另外,一些页面呈现确定。 不想用代码填充此问题,因此如果您需要更多信息,我很乐意提供。由于
编辑
所以,这里是我的观点:
@login_required
def tasks(request, msg=''):
tasks = Task.objects.all()
message = msg
return custom_render('user/tasks.html',
{'tasks': tasks, 'message':message},
request)
这里是我的模板:
{% block main_content %}
{% if message %}
<p id="message" class="info">
{{message}}
</p>
{% endif %}
<a href="{% url GProject.myapp.views.new_task %}">Nueva Tarea</a>
<table id="tasks-table" >
<thead>
<tr>
<th colspan="4" >{{tasks|length}} tareas pendientes</th>
</tr>
<tr>
<th>#</th>
<th>Proyecto</th>
<th>Título</th>
<th>Estado</th>
</tr>
</thead>
<tbody>
{% for t in tasks %}
<tr id="row-{{t.id}}" class="{% cycle 'row-0' 'row-1' %} priority-{{ t.priority }}">
<td width="25">
<a href="{% url GProject.myapp.views.view_task t.id %}">{{t.id}}</a>
</td>
<td>
<a href="{% url GProject.myapp.views.view_task t.id %}">{{t.project}}</a>
</td>
<td width="400">
<a href="{% url GProject.myapp.views.view_task t.id %}">
{{t.title}}
</a>
</td>
<td>{{t.get_status_display}}</td>
</tr>
{% empty %}
<tr><td>No tasks</td></tr>
{% endfor %}
</tbody>
</table>
{% endblock main_content %}
而且,现在我就在这错误 :
TypeError at /admin/tareas/
argument 1 must be a string or unicode object
Request Method: GET
Request URL: http://localhost/gpro/admin/tareas/
Exception Type: TypeError
Exception Value:
argument 1 must be a string or unicode object
Exception Location: /usr/local/lib/python2.6/dist-packages/django/db/backends/postgresql_psycopg2/base.py in _cursor, line 105
Python Executable: /usr/bin/python
Python Version: 2.5.4
编辑
任务模式是这样的:
class Task(models.Model):
project = models.ForeignKey(Project)
title = models.CharField(max_length=128)
description = models.TextField(max_length=1500)
effort = models.IntegerField(null=True, blank=True)
priority = models.IntegerField(max_length=1, null=True, blank=True, choices=PRIORITY_VALUES)
severity = models.IntegerField(max_length=1, null=True, blank=True, choices=SEVERITY_VALUES)
asignee = models.ForeignKey(User, blank=True, null=True, related_name='asignee')
milestone = models.ForeignKey(Milestone, blank=True, null=True)
created_by = models.ForeignKey(User, blank=True, null=True, related_name='created_by')
status = models.IntegerField(max_length=1, choices=STATUS_VALUES, default=1)
resolution_comment = models.CharField(max_length=1500, null=True, blank=True) #comentario al resolver la task
due_date = models.DateField(blank=True, null=True)
created_on = models.DateTimeField(auto_now_add = True)
#print
def __unicode__(self):
return self.title
custom_render:
def custom_render(template_name, data_dict, request):
return render_to_response(template_name,
data_dict,
context_instance=RequestContext(request))
你可以修改Django源代码和打印repr的sql和params? 当代码下devserver和Apache – 2010-03-14 21:45:00
彼得跑了,我真的不知道该怎么做.. – Nacho 2010-03-15 01:42:24
Django不总是指出模板的正确路线。不要太信任它。 – Macke 2010-03-20 18:52:37