人们向我推荐我应该将此代码转换为jquery,但是如何以及在哪里,是否有任何工具或者如何执行此操作以及为什么XMLHttpRequest不适合jQuery?如何将普通JavaScript代码转换为jQuery
我有这样的代码:
function showVal(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "* Please type in School Name.";
return;
}
if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4) {
if (xmlhttp.status == 200) { // break this into 2 statements so you can handle HTTP errors
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
} else {
document.getElementById("txtHint").innerHTML = "AJAX Error (HTTP "+xmlhttp.status+")";
}
}
}; // functions declared in this way should be followed by a semi colon, since the function declaration is actually a statement.
// encodeURIComponent() does all the escaping work for you - it is roughly analogous to PHP's urlencode()
// xmlhttp.open("GET","ajaxFuncs2.php?q="+encodeURIComponent(str),true);
xmlhttp.open("GET","ajaxFuncs2.php?q="+encodeURIComponent(str),true);
xmlhttp.send();
}
你应该了解jQuery的一些文档开始。从官方网站开始http://docs.jquery.com/How_jQuery_Works – 2012-01-17 17:09:46
如果有效,可能没有任何理由需要切换。事实上,如果您现在不使用(并加载)jQuery,那么转换为jQuery只会增加页面的大小。 – 2012-01-17 17:10:06
它不适用于我的其他jQuery代码:S – Drazek 2012-01-17 17:12:39