你好,我做了PHP类为我的数据库,我使用的XAMPP在Windows 10PHP数据库类,或使用类的代码是不工作
似乎什么是错的,我不能发现问题,我不知道它在我的类文件或我inex.php文件
这做的是错误:
致命错误:未捕获的错误:类“DB”在d未找到: \ XAMP \ htdocs中\ telepol \ userInfo.php:5堆栈跟踪:#0 d:\ XAMP \ htdocs中\ telepol \ userInfo.php(43):showData()#1 {主}抛出d:\ XAMP \ htdocs中\第5行telepol \ userInfo.php
db.php中
<? php
class db{
private $_conn;
private $_host = "localhost";
private $_username = "root";
private $_psw = "";
private $_dbName = "users";
public function __construct(){
$this->_conn = new mysqli($this->_host, $this->_username, $this->_psw, $this->_dbName);
if ($this->_conn->connect_error){
die("Connection failed: " . $this->_conn->connect_error);
}
}
public function getCon(){
return $this->_conn;
}
}
?>
userInfo.php
<?php
require_once 'classes/db.php';
function showData(){
$conn = new db();
$br = 1; //br is used to displat the number of each row in the table.
$userQuery = "SELECT* FROM users";
$result = $conn->getCon()->query($userQuery);
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {
echo "<tr> <td>" .$br ."</td> <td>" .$row["first_name"] ."</td> <td>" .$row["last_name"] ."</td> <td>" .$row["nickname"] ."</td> <td>" .$row["user_id"] ."</td> <br>" ;
$br ++;
}
}
$conn->close();
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Users Info</title>
<!-- adding JS scripts -->
<script type="text/javascript" src="jquery-3.1.1.min.js"></script>
<!-- adding css -->
<link rel="stylesheet" href="css/bootstrap.css">
<link rel="stylesheet" href="css/bootstrap.min.css">
<!-- my CSS -->
<link rel="stylesheet" href="css/style.css">
</head>
<body>
<table class="table table-striped table-bordered table-hover table-sm">
<thead class="thead-default">
<tr>
<th>#</th>
<th>First Name</th>
<th>Last Name</th>
<th>Nickname</th>
<th>User ID</th>
</tr>
</thead>
<?php showData(); ?>
</table>
</body>
</html>
我不知道,如何解决它。我试过 '$ database = new db(); $ conn = $ database-> getCon(); ' 还是老样子不工作 –
这可能是因为你的'__construct'功能是私人在'db.php' –
在这里其他方面的建议以及实例您的mysqli类,当你有一个错字。你有msqli,应该是mysqli,你错过了“y”。 – Jase