独立JSON结果到变量

Question

我有以下生成的JSON结果，并想找出我如何可以将结果分为2个变量：

JSON

{ 
    "data": [ 
     [ 
      { 
       "source": "server1", 
       "host": "pc1", 
       "description": "SSH server is down on {HOSTNAME}", 
      } 
     ], 
     [ 
      { 
       "source": "server2", 
       "host": "pc2", 
       "description": "webapp down", 
      } 
     ] 
    ], 
    "error": { 
     "server3": "Host is not allowed to connect to this MySQL server", 
     "server4": "Can't connect to MySQL server", 
    } 
} 

预期的结果：

{ 
    "data": [ 
      { 
       "source": "server1", 
       "host": "pc1", 
       "description": "SSH server is down on {HOSTNAME}", 
      }, 
      { 
       "source": "server2", 
       "host": "pc2", 
       "description": "webapp down", 
      } 
     ] 
} 

而且

{ 
    "error": { 
     "server3": "Host is not allowed to connect to this MySQL server", 
     "server4": "Can't connect to MySQL server", 
    } 
} 

PHP代码：

<?php 
    include '../include/db_conn.php'; 
    print to_json(get_all_alert()); 
$return = get_all_alert(); 
print to_json($return["data"]); 
print to_json($return["error"]); 
?> 

php代码仍然打印结果两次。谢谢

Answer 1

那么，你有一个额外的线，你可能不需要。

print to_json(get_all_alert());

删除，你的问题很可能会消失。

Answer 2

你的json数据不正确，你可以在这里查看：http://json.parser.online.fr/ 从每个数组部分删除额外的逗号。

试试这个：

<?php 
$data1='{ 
    "data": [ 
     [ 
      { 
       "source": "server1", 
       "host": "pc1", 
       "description": "SSH server is down on {HOSTNAME}" 
      } 
     ], 
     [ 
      { 
       "source": "server2", 
       "host": "pc2", 
       "description": "webapp down" 
      } 
     ] 
    ], 
    "error": { 
     "server3": "Host is not allowed to connect to this MySQL server", 
     "server4": "Cant connect to MySQL server" 
    } 
}'; 

$val_array = json_decode($data1,true); 

print_r($val_array['data']); 
print_r($val_array['error']);