Sequelize MySQL从同一个表中选择（左连接）

如何从同一个表中选择两次Sequelize？这里是MySQL代码：Sequelize MySQL从同一个表中选择（左连接）

select b.*, a.parent_id 
from theSameTable as b left join theSameTable as a on b.parent_id = a.id

这里是我的MySQL表

这里是我的Sequelize代码

const db = await ec.sequelize.define(tableDb, { 
    id: { 
     type: ec.Sequelize.INTEGER.UNSIGNED, 
     primaryKey: true, 
     autoIncrement: true 
    }, 
    url: ec.Sequelize.STRING(511), 
    url_hash: ec.Sequelize.STRING(32), 
    name: ec.Sequelize.STRING(511), 
    full_name: ec.Sequelize.STRING(511), 
    parent_id: ec.Sequelize.INTEGER(11).UNSIGNED, 
    cnt: ec.Sequelize.STRING(255), 
    chk: ec.Sequelize.INTEGER(1) 
}, { 
    indexes: [{ 
     unique: true, 
     fields: ['url_hash'] 
    }] 
}); 

await ec.sequelize.sync();

来源

2017-10-18 big.data

你是怎么找到谷歌上搜索有关自联接的sequelize？ – philipxy

[使用Sequelize查询自连接，包括相关记录]的可能重复（https://stackoverflow.com/questions/40294776/query-self-join-with-sequelize-including-related-record） – philipxy

最后我找到了答案。也许对某人会有用。后

await ec.sequelize.sync();

写

db.belongsTo(db, { 
    as: 'db2', 
    foreignKey: 'parent_id', 
    required: false 
}); 

let rows = await db.findAll({ 
    where: { 
     chk: 0 
    }, 
    include: [{ 
     model: db, 
     as: 'db2', 
     attributes: ['id', 'full_name'] 
    }], 
    raw: true, 
    limit: 20 
}).catch(function (err) { 
    console.log(err); 
});

来源

2017-10-19 13:12:49

Sequelize MySQL从同一个表中选择（左连接）

回答

相关问题